1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 128 541 ÷ 2 = 64 270 + 1;
- 64 270 ÷ 2 = 32 135 + 0;
- 32 135 ÷ 2 = 16 067 + 1;
- 16 067 ÷ 2 = 8 033 + 1;
- 8 033 ÷ 2 = 4 016 + 1;
- 4 016 ÷ 2 = 2 008 + 0;
- 2 008 ÷ 2 = 1 004 + 0;
- 1 004 ÷ 2 = 502 + 0;
- 502 ÷ 2 = 251 + 0;
- 251 ÷ 2 = 125 + 1;
- 125 ÷ 2 = 62 + 1;
- 62 ÷ 2 = 31 + 0;
- 31 ÷ 2 = 15 + 1;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
128 541(10) = 1 1111 0110 0001 1101(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 17.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 17,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Number 128 541(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
128 541(10) = 0000 0000 0000 0001 1111 0110 0001 1101
Spaces were used to group digits: for binary, by 4, for decimal, by 3.