1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 111 111 111 105 ÷ 2 = 555 555 555 552 + 1;
- 555 555 555 552 ÷ 2 = 277 777 777 776 + 0;
- 277 777 777 776 ÷ 2 = 138 888 888 888 + 0;
- 138 888 888 888 ÷ 2 = 69 444 444 444 + 0;
- 69 444 444 444 ÷ 2 = 34 722 222 222 + 0;
- 34 722 222 222 ÷ 2 = 17 361 111 111 + 0;
- 17 361 111 111 ÷ 2 = 8 680 555 555 + 1;
- 8 680 555 555 ÷ 2 = 4 340 277 777 + 1;
- 4 340 277 777 ÷ 2 = 2 170 138 888 + 1;
- 2 170 138 888 ÷ 2 = 1 085 069 444 + 0;
- 1 085 069 444 ÷ 2 = 542 534 722 + 0;
- 542 534 722 ÷ 2 = 271 267 361 + 0;
- 271 267 361 ÷ 2 = 135 633 680 + 1;
- 135 633 680 ÷ 2 = 67 816 840 + 0;
- 67 816 840 ÷ 2 = 33 908 420 + 0;
- 33 908 420 ÷ 2 = 16 954 210 + 0;
- 16 954 210 ÷ 2 = 8 477 105 + 0;
- 8 477 105 ÷ 2 = 4 238 552 + 1;
- 4 238 552 ÷ 2 = 2 119 276 + 0;
- 2 119 276 ÷ 2 = 1 059 638 + 0;
- 1 059 638 ÷ 2 = 529 819 + 0;
- 529 819 ÷ 2 = 264 909 + 1;
- 264 909 ÷ 2 = 132 454 + 1;
- 132 454 ÷ 2 = 66 227 + 0;
- 66 227 ÷ 2 = 33 113 + 1;
- 33 113 ÷ 2 = 16 556 + 1;
- 16 556 ÷ 2 = 8 278 + 0;
- 8 278 ÷ 2 = 4 139 + 0;
- 4 139 ÷ 2 = 2 069 + 1;
- 2 069 ÷ 2 = 1 034 + 1;
- 1 034 ÷ 2 = 517 + 0;
- 517 ÷ 2 = 258 + 1;
- 258 ÷ 2 = 129 + 0;
- 129 ÷ 2 = 64 + 1;
- 64 ÷ 2 = 32 + 0;
- 32 ÷ 2 = 16 + 0;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 111 111 111 105(10) = 1 0000 0010 1011 0011 0110 0010 0001 0001 1100 0001(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 41.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 41,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 1 111 111 111 105(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.