1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 111 101 100 073 ÷ 2 = 555 550 550 036 + 1;
- 555 550 550 036 ÷ 2 = 277 775 275 018 + 0;
- 277 775 275 018 ÷ 2 = 138 887 637 509 + 0;
- 138 887 637 509 ÷ 2 = 69 443 818 754 + 1;
- 69 443 818 754 ÷ 2 = 34 721 909 377 + 0;
- 34 721 909 377 ÷ 2 = 17 360 954 688 + 1;
- 17 360 954 688 ÷ 2 = 8 680 477 344 + 0;
- 8 680 477 344 ÷ 2 = 4 340 238 672 + 0;
- 4 340 238 672 ÷ 2 = 2 170 119 336 + 0;
- 2 170 119 336 ÷ 2 = 1 085 059 668 + 0;
- 1 085 059 668 ÷ 2 = 542 529 834 + 0;
- 542 529 834 ÷ 2 = 271 264 917 + 0;
- 271 264 917 ÷ 2 = 135 632 458 + 1;
- 135 632 458 ÷ 2 = 67 816 229 + 0;
- 67 816 229 ÷ 2 = 33 908 114 + 1;
- 33 908 114 ÷ 2 = 16 954 057 + 0;
- 16 954 057 ÷ 2 = 8 477 028 + 1;
- 8 477 028 ÷ 2 = 4 238 514 + 0;
- 4 238 514 ÷ 2 = 2 119 257 + 0;
- 2 119 257 ÷ 2 = 1 059 628 + 1;
- 1 059 628 ÷ 2 = 529 814 + 0;
- 529 814 ÷ 2 = 264 907 + 0;
- 264 907 ÷ 2 = 132 453 + 1;
- 132 453 ÷ 2 = 66 226 + 1;
- 66 226 ÷ 2 = 33 113 + 0;
- 33 113 ÷ 2 = 16 556 + 1;
- 16 556 ÷ 2 = 8 278 + 0;
- 8 278 ÷ 2 = 4 139 + 0;
- 4 139 ÷ 2 = 2 069 + 1;
- 2 069 ÷ 2 = 1 034 + 1;
- 1 034 ÷ 2 = 517 + 0;
- 517 ÷ 2 = 258 + 1;
- 258 ÷ 2 = 129 + 0;
- 129 ÷ 2 = 64 + 1;
- 64 ÷ 2 = 32 + 0;
- 32 ÷ 2 = 16 + 0;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 111 101 100 073(10) = 1 0000 0010 1011 0010 1100 1001 0101 0000 0010 1001(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 41.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 41,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 1 111 101 100 073(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.