1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 111 011 111 011 154 ÷ 2 = 555 505 555 505 577 + 0;
- 555 505 555 505 577 ÷ 2 = 277 752 777 752 788 + 1;
- 277 752 777 752 788 ÷ 2 = 138 876 388 876 394 + 0;
- 138 876 388 876 394 ÷ 2 = 69 438 194 438 197 + 0;
- 69 438 194 438 197 ÷ 2 = 34 719 097 219 098 + 1;
- 34 719 097 219 098 ÷ 2 = 17 359 548 609 549 + 0;
- 17 359 548 609 549 ÷ 2 = 8 679 774 304 774 + 1;
- 8 679 774 304 774 ÷ 2 = 4 339 887 152 387 + 0;
- 4 339 887 152 387 ÷ 2 = 2 169 943 576 193 + 1;
- 2 169 943 576 193 ÷ 2 = 1 084 971 788 096 + 1;
- 1 084 971 788 096 ÷ 2 = 542 485 894 048 + 0;
- 542 485 894 048 ÷ 2 = 271 242 947 024 + 0;
- 271 242 947 024 ÷ 2 = 135 621 473 512 + 0;
- 135 621 473 512 ÷ 2 = 67 810 736 756 + 0;
- 67 810 736 756 ÷ 2 = 33 905 368 378 + 0;
- 33 905 368 378 ÷ 2 = 16 952 684 189 + 0;
- 16 952 684 189 ÷ 2 = 8 476 342 094 + 1;
- 8 476 342 094 ÷ 2 = 4 238 171 047 + 0;
- 4 238 171 047 ÷ 2 = 2 119 085 523 + 1;
- 2 119 085 523 ÷ 2 = 1 059 542 761 + 1;
- 1 059 542 761 ÷ 2 = 529 771 380 + 1;
- 529 771 380 ÷ 2 = 264 885 690 + 0;
- 264 885 690 ÷ 2 = 132 442 845 + 0;
- 132 442 845 ÷ 2 = 66 221 422 + 1;
- 66 221 422 ÷ 2 = 33 110 711 + 0;
- 33 110 711 ÷ 2 = 16 555 355 + 1;
- 16 555 355 ÷ 2 = 8 277 677 + 1;
- 8 277 677 ÷ 2 = 4 138 838 + 1;
- 4 138 838 ÷ 2 = 2 069 419 + 0;
- 2 069 419 ÷ 2 = 1 034 709 + 1;
- 1 034 709 ÷ 2 = 517 354 + 1;
- 517 354 ÷ 2 = 258 677 + 0;
- 258 677 ÷ 2 = 129 338 + 1;
- 129 338 ÷ 2 = 64 669 + 0;
- 64 669 ÷ 2 = 32 334 + 1;
- 32 334 ÷ 2 = 16 167 + 0;
- 16 167 ÷ 2 = 8 083 + 1;
- 8 083 ÷ 2 = 4 041 + 1;
- 4 041 ÷ 2 = 2 020 + 1;
- 2 020 ÷ 2 = 1 010 + 0;
- 1 010 ÷ 2 = 505 + 0;
- 505 ÷ 2 = 252 + 1;
- 252 ÷ 2 = 126 + 0;
- 126 ÷ 2 = 63 + 0;
- 63 ÷ 2 = 31 + 1;
- 31 ÷ 2 = 15 + 1;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 111 011 111 011 154(10) = 11 1111 0010 0111 0101 0110 1110 1001 1101 0000 0011 0101 0010(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Number 1 111 011 111 011 154(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
1 111 011 111 011 154(10) = 0000 0000 0000 0011 1111 0010 0111 0101 0110 1110 1001 1101 0000 0011 0101 0010
Spaces were used to group digits: for binary, by 4, for decimal, by 3.