1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 111 011 000 999 965 ÷ 2 = 55 505 500 499 982 + 1;
- 55 505 500 499 982 ÷ 2 = 27 752 750 249 991 + 0;
- 27 752 750 249 991 ÷ 2 = 13 876 375 124 995 + 1;
- 13 876 375 124 995 ÷ 2 = 6 938 187 562 497 + 1;
- 6 938 187 562 497 ÷ 2 = 3 469 093 781 248 + 1;
- 3 469 093 781 248 ÷ 2 = 1 734 546 890 624 + 0;
- 1 734 546 890 624 ÷ 2 = 867 273 445 312 + 0;
- 867 273 445 312 ÷ 2 = 433 636 722 656 + 0;
- 433 636 722 656 ÷ 2 = 216 818 361 328 + 0;
- 216 818 361 328 ÷ 2 = 108 409 180 664 + 0;
- 108 409 180 664 ÷ 2 = 54 204 590 332 + 0;
- 54 204 590 332 ÷ 2 = 27 102 295 166 + 0;
- 27 102 295 166 ÷ 2 = 13 551 147 583 + 0;
- 13 551 147 583 ÷ 2 = 6 775 573 791 + 1;
- 6 775 573 791 ÷ 2 = 3 387 786 895 + 1;
- 3 387 786 895 ÷ 2 = 1 693 893 447 + 1;
- 1 693 893 447 ÷ 2 = 846 946 723 + 1;
- 846 946 723 ÷ 2 = 423 473 361 + 1;
- 423 473 361 ÷ 2 = 211 736 680 + 1;
- 211 736 680 ÷ 2 = 105 868 340 + 0;
- 105 868 340 ÷ 2 = 52 934 170 + 0;
- 52 934 170 ÷ 2 = 26 467 085 + 0;
- 26 467 085 ÷ 2 = 13 233 542 + 1;
- 13 233 542 ÷ 2 = 6 616 771 + 0;
- 6 616 771 ÷ 2 = 3 308 385 + 1;
- 3 308 385 ÷ 2 = 1 654 192 + 1;
- 1 654 192 ÷ 2 = 827 096 + 0;
- 827 096 ÷ 2 = 413 548 + 0;
- 413 548 ÷ 2 = 206 774 + 0;
- 206 774 ÷ 2 = 103 387 + 0;
- 103 387 ÷ 2 = 51 693 + 1;
- 51 693 ÷ 2 = 25 846 + 1;
- 25 846 ÷ 2 = 12 923 + 0;
- 12 923 ÷ 2 = 6 461 + 1;
- 6 461 ÷ 2 = 3 230 + 1;
- 3 230 ÷ 2 = 1 615 + 0;
- 1 615 ÷ 2 = 807 + 1;
- 807 ÷ 2 = 403 + 1;
- 403 ÷ 2 = 201 + 1;
- 201 ÷ 2 = 100 + 1;
- 100 ÷ 2 = 50 + 0;
- 50 ÷ 2 = 25 + 0;
- 25 ÷ 2 = 12 + 1;
- 12 ÷ 2 = 6 + 0;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
111 011 000 999 965(10) = 110 0100 1111 0110 1100 0011 0100 0111 1110 0000 0001 1101(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 47.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 47,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Number 111 011 000 999 965(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
111 011 000 999 965(10) = 0000 0000 0000 0000 0110 0100 1111 0110 1100 0011 0100 0111 1110 0000 0001 1101
Spaces were used to group digits: for binary, by 4, for decimal, by 3.