1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 110 111 101 101 068 ÷ 2 = 55 055 550 550 534 + 0;
- 55 055 550 550 534 ÷ 2 = 27 527 775 275 267 + 0;
- 27 527 775 275 267 ÷ 2 = 13 763 887 637 633 + 1;
- 13 763 887 637 633 ÷ 2 = 6 881 943 818 816 + 1;
- 6 881 943 818 816 ÷ 2 = 3 440 971 909 408 + 0;
- 3 440 971 909 408 ÷ 2 = 1 720 485 954 704 + 0;
- 1 720 485 954 704 ÷ 2 = 860 242 977 352 + 0;
- 860 242 977 352 ÷ 2 = 430 121 488 676 + 0;
- 430 121 488 676 ÷ 2 = 215 060 744 338 + 0;
- 215 060 744 338 ÷ 2 = 107 530 372 169 + 0;
- 107 530 372 169 ÷ 2 = 53 765 186 084 + 1;
- 53 765 186 084 ÷ 2 = 26 882 593 042 + 0;
- 26 882 593 042 ÷ 2 = 13 441 296 521 + 0;
- 13 441 296 521 ÷ 2 = 6 720 648 260 + 1;
- 6 720 648 260 ÷ 2 = 3 360 324 130 + 0;
- 3 360 324 130 ÷ 2 = 1 680 162 065 + 0;
- 1 680 162 065 ÷ 2 = 840 081 032 + 1;
- 840 081 032 ÷ 2 = 420 040 516 + 0;
- 420 040 516 ÷ 2 = 210 020 258 + 0;
- 210 020 258 ÷ 2 = 105 010 129 + 0;
- 105 010 129 ÷ 2 = 52 505 064 + 1;
- 52 505 064 ÷ 2 = 26 252 532 + 0;
- 26 252 532 ÷ 2 = 13 126 266 + 0;
- 13 126 266 ÷ 2 = 6 563 133 + 0;
- 6 563 133 ÷ 2 = 3 281 566 + 1;
- 3 281 566 ÷ 2 = 1 640 783 + 0;
- 1 640 783 ÷ 2 = 820 391 + 1;
- 820 391 ÷ 2 = 410 195 + 1;
- 410 195 ÷ 2 = 205 097 + 1;
- 205 097 ÷ 2 = 102 548 + 1;
- 102 548 ÷ 2 = 51 274 + 0;
- 51 274 ÷ 2 = 25 637 + 0;
- 25 637 ÷ 2 = 12 818 + 1;
- 12 818 ÷ 2 = 6 409 + 0;
- 6 409 ÷ 2 = 3 204 + 1;
- 3 204 ÷ 2 = 1 602 + 0;
- 1 602 ÷ 2 = 801 + 0;
- 801 ÷ 2 = 400 + 1;
- 400 ÷ 2 = 200 + 0;
- 200 ÷ 2 = 100 + 0;
- 100 ÷ 2 = 50 + 0;
- 50 ÷ 2 = 25 + 0;
- 25 ÷ 2 = 12 + 1;
- 12 ÷ 2 = 6 + 0;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
110 111 101 101 068(10) = 110 0100 0010 0101 0011 1101 0001 0001 0010 0100 0000 1100(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 47.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 47,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 110 111 101 101 068(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.