1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 100 110 010 110 022 ÷ 2 = 550 055 005 055 011 + 0;
- 550 055 005 055 011 ÷ 2 = 275 027 502 527 505 + 1;
- 275 027 502 527 505 ÷ 2 = 137 513 751 263 752 + 1;
- 137 513 751 263 752 ÷ 2 = 68 756 875 631 876 + 0;
- 68 756 875 631 876 ÷ 2 = 34 378 437 815 938 + 0;
- 34 378 437 815 938 ÷ 2 = 17 189 218 907 969 + 0;
- 17 189 218 907 969 ÷ 2 = 8 594 609 453 984 + 1;
- 8 594 609 453 984 ÷ 2 = 4 297 304 726 992 + 0;
- 4 297 304 726 992 ÷ 2 = 2 148 652 363 496 + 0;
- 2 148 652 363 496 ÷ 2 = 1 074 326 181 748 + 0;
- 1 074 326 181 748 ÷ 2 = 537 163 090 874 + 0;
- 537 163 090 874 ÷ 2 = 268 581 545 437 + 0;
- 268 581 545 437 ÷ 2 = 134 290 772 718 + 1;
- 134 290 772 718 ÷ 2 = 67 145 386 359 + 0;
- 67 145 386 359 ÷ 2 = 33 572 693 179 + 1;
- 33 572 693 179 ÷ 2 = 16 786 346 589 + 1;
- 16 786 346 589 ÷ 2 = 8 393 173 294 + 1;
- 8 393 173 294 ÷ 2 = 4 196 586 647 + 0;
- 4 196 586 647 ÷ 2 = 2 098 293 323 + 1;
- 2 098 293 323 ÷ 2 = 1 049 146 661 + 1;
- 1 049 146 661 ÷ 2 = 524 573 330 + 1;
- 524 573 330 ÷ 2 = 262 286 665 + 0;
- 262 286 665 ÷ 2 = 131 143 332 + 1;
- 131 143 332 ÷ 2 = 65 571 666 + 0;
- 65 571 666 ÷ 2 = 32 785 833 + 0;
- 32 785 833 ÷ 2 = 16 392 916 + 1;
- 16 392 916 ÷ 2 = 8 196 458 + 0;
- 8 196 458 ÷ 2 = 4 098 229 + 0;
- 4 098 229 ÷ 2 = 2 049 114 + 1;
- 2 049 114 ÷ 2 = 1 024 557 + 0;
- 1 024 557 ÷ 2 = 512 278 + 1;
- 512 278 ÷ 2 = 256 139 + 0;
- 256 139 ÷ 2 = 128 069 + 1;
- 128 069 ÷ 2 = 64 034 + 1;
- 64 034 ÷ 2 = 32 017 + 0;
- 32 017 ÷ 2 = 16 008 + 1;
- 16 008 ÷ 2 = 8 004 + 0;
- 8 004 ÷ 2 = 4 002 + 0;
- 4 002 ÷ 2 = 2 001 + 0;
- 2 001 ÷ 2 = 1 000 + 1;
- 1 000 ÷ 2 = 500 + 0;
- 500 ÷ 2 = 250 + 0;
- 250 ÷ 2 = 125 + 0;
- 125 ÷ 2 = 62 + 1;
- 62 ÷ 2 = 31 + 0;
- 31 ÷ 2 = 15 + 1;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 100 110 010 110 022(10) = 11 1110 1000 1000 1011 0101 0010 0101 1101 1101 0000 0100 0110(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Number 1 100 110 010 110 022(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
1 100 110 010 110 022(10) = 0000 0000 0000 0011 1110 1000 1000 1011 0101 0010 0101 1101 1101 0000 0100 0110
Spaces were used to group digits: for binary, by 4, for decimal, by 3.