1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 11 000 110 111 000 092 ÷ 2 = 5 500 055 055 500 046 + 0;
- 5 500 055 055 500 046 ÷ 2 = 2 750 027 527 750 023 + 0;
- 2 750 027 527 750 023 ÷ 2 = 1 375 013 763 875 011 + 1;
- 1 375 013 763 875 011 ÷ 2 = 687 506 881 937 505 + 1;
- 687 506 881 937 505 ÷ 2 = 343 753 440 968 752 + 1;
- 343 753 440 968 752 ÷ 2 = 171 876 720 484 376 + 0;
- 171 876 720 484 376 ÷ 2 = 85 938 360 242 188 + 0;
- 85 938 360 242 188 ÷ 2 = 42 969 180 121 094 + 0;
- 42 969 180 121 094 ÷ 2 = 21 484 590 060 547 + 0;
- 21 484 590 060 547 ÷ 2 = 10 742 295 030 273 + 1;
- 10 742 295 030 273 ÷ 2 = 5 371 147 515 136 + 1;
- 5 371 147 515 136 ÷ 2 = 2 685 573 757 568 + 0;
- 2 685 573 757 568 ÷ 2 = 1 342 786 878 784 + 0;
- 1 342 786 878 784 ÷ 2 = 671 393 439 392 + 0;
- 671 393 439 392 ÷ 2 = 335 696 719 696 + 0;
- 335 696 719 696 ÷ 2 = 167 848 359 848 + 0;
- 167 848 359 848 ÷ 2 = 83 924 179 924 + 0;
- 83 924 179 924 ÷ 2 = 41 962 089 962 + 0;
- 41 962 089 962 ÷ 2 = 20 981 044 981 + 0;
- 20 981 044 981 ÷ 2 = 10 490 522 490 + 1;
- 10 490 522 490 ÷ 2 = 5 245 261 245 + 0;
- 5 245 261 245 ÷ 2 = 2 622 630 622 + 1;
- 2 622 630 622 ÷ 2 = 1 311 315 311 + 0;
- 1 311 315 311 ÷ 2 = 655 657 655 + 1;
- 655 657 655 ÷ 2 = 327 828 827 + 1;
- 327 828 827 ÷ 2 = 163 914 413 + 1;
- 163 914 413 ÷ 2 = 81 957 206 + 1;
- 81 957 206 ÷ 2 = 40 978 603 + 0;
- 40 978 603 ÷ 2 = 20 489 301 + 1;
- 20 489 301 ÷ 2 = 10 244 650 + 1;
- 10 244 650 ÷ 2 = 5 122 325 + 0;
- 5 122 325 ÷ 2 = 2 561 162 + 1;
- 2 561 162 ÷ 2 = 1 280 581 + 0;
- 1 280 581 ÷ 2 = 640 290 + 1;
- 640 290 ÷ 2 = 320 145 + 0;
- 320 145 ÷ 2 = 160 072 + 1;
- 160 072 ÷ 2 = 80 036 + 0;
- 80 036 ÷ 2 = 40 018 + 0;
- 40 018 ÷ 2 = 20 009 + 0;
- 20 009 ÷ 2 = 10 004 + 1;
- 10 004 ÷ 2 = 5 002 + 0;
- 5 002 ÷ 2 = 2 501 + 0;
- 2 501 ÷ 2 = 1 250 + 1;
- 1 250 ÷ 2 = 625 + 0;
- 625 ÷ 2 = 312 + 1;
- 312 ÷ 2 = 156 + 0;
- 156 ÷ 2 = 78 + 0;
- 78 ÷ 2 = 39 + 0;
- 39 ÷ 2 = 19 + 1;
- 19 ÷ 2 = 9 + 1;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
11 000 110 111 000 092(10) = 10 0111 0001 0100 1000 1010 1011 0111 1010 1000 0000 0110 0001 1100(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 54.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 54,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Number 11 000 110 111 000 092(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
11 000 110 111 000 092(10) = 0000 0000 0010 0111 0001 0100 1000 1010 1011 0111 1010 1000 0000 0110 0001 1100
Spaces were used to group digits: for binary, by 4, for decimal, by 3.