1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 11 000 011 110 009 890 ÷ 2 = 5 500 005 555 004 945 + 0;
- 5 500 005 555 004 945 ÷ 2 = 2 750 002 777 502 472 + 1;
- 2 750 002 777 502 472 ÷ 2 = 1 375 001 388 751 236 + 0;
- 1 375 001 388 751 236 ÷ 2 = 687 500 694 375 618 + 0;
- 687 500 694 375 618 ÷ 2 = 343 750 347 187 809 + 0;
- 343 750 347 187 809 ÷ 2 = 171 875 173 593 904 + 1;
- 171 875 173 593 904 ÷ 2 = 85 937 586 796 952 + 0;
- 85 937 586 796 952 ÷ 2 = 42 968 793 398 476 + 0;
- 42 968 793 398 476 ÷ 2 = 21 484 396 699 238 + 0;
- 21 484 396 699 238 ÷ 2 = 10 742 198 349 619 + 0;
- 10 742 198 349 619 ÷ 2 = 5 371 099 174 809 + 1;
- 5 371 099 174 809 ÷ 2 = 2 685 549 587 404 + 1;
- 2 685 549 587 404 ÷ 2 = 1 342 774 793 702 + 0;
- 1 342 774 793 702 ÷ 2 = 671 387 396 851 + 0;
- 671 387 396 851 ÷ 2 = 335 693 698 425 + 1;
- 335 693 698 425 ÷ 2 = 167 846 849 212 + 1;
- 167 846 849 212 ÷ 2 = 83 923 424 606 + 0;
- 83 923 424 606 ÷ 2 = 41 961 712 303 + 0;
- 41 961 712 303 ÷ 2 = 20 980 856 151 + 1;
- 20 980 856 151 ÷ 2 = 10 490 428 075 + 1;
- 10 490 428 075 ÷ 2 = 5 245 214 037 + 1;
- 5 245 214 037 ÷ 2 = 2 622 607 018 + 1;
- 2 622 607 018 ÷ 2 = 1 311 303 509 + 0;
- 1 311 303 509 ÷ 2 = 655 651 754 + 1;
- 655 651 754 ÷ 2 = 327 825 877 + 0;
- 327 825 877 ÷ 2 = 163 912 938 + 1;
- 163 912 938 ÷ 2 = 81 956 469 + 0;
- 81 956 469 ÷ 2 = 40 978 234 + 1;
- 40 978 234 ÷ 2 = 20 489 117 + 0;
- 20 489 117 ÷ 2 = 10 244 558 + 1;
- 10 244 558 ÷ 2 = 5 122 279 + 0;
- 5 122 279 ÷ 2 = 2 561 139 + 1;
- 2 561 139 ÷ 2 = 1 280 569 + 1;
- 1 280 569 ÷ 2 = 640 284 + 1;
- 640 284 ÷ 2 = 320 142 + 0;
- 320 142 ÷ 2 = 160 071 + 0;
- 160 071 ÷ 2 = 80 035 + 1;
- 80 035 ÷ 2 = 40 017 + 1;
- 40 017 ÷ 2 = 20 008 + 1;
- 20 008 ÷ 2 = 10 004 + 0;
- 10 004 ÷ 2 = 5 002 + 0;
- 5 002 ÷ 2 = 2 501 + 0;
- 2 501 ÷ 2 = 1 250 + 1;
- 1 250 ÷ 2 = 625 + 0;
- 625 ÷ 2 = 312 + 1;
- 312 ÷ 2 = 156 + 0;
- 156 ÷ 2 = 78 + 0;
- 78 ÷ 2 = 39 + 0;
- 39 ÷ 2 = 19 + 1;
- 19 ÷ 2 = 9 + 1;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
11 000 011 110 009 890(10) = 10 0111 0001 0100 0111 0011 1010 1010 1011 1100 1100 1100 0010 0010(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 54.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 54,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 11 000 011 110 009 890(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.