1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 100 001 009 209 ÷ 2 = 550 000 504 604 + 1;
- 550 000 504 604 ÷ 2 = 275 000 252 302 + 0;
- 275 000 252 302 ÷ 2 = 137 500 126 151 + 0;
- 137 500 126 151 ÷ 2 = 68 750 063 075 + 1;
- 68 750 063 075 ÷ 2 = 34 375 031 537 + 1;
- 34 375 031 537 ÷ 2 = 17 187 515 768 + 1;
- 17 187 515 768 ÷ 2 = 8 593 757 884 + 0;
- 8 593 757 884 ÷ 2 = 4 296 878 942 + 0;
- 4 296 878 942 ÷ 2 = 2 148 439 471 + 0;
- 2 148 439 471 ÷ 2 = 1 074 219 735 + 1;
- 1 074 219 735 ÷ 2 = 537 109 867 + 1;
- 537 109 867 ÷ 2 = 268 554 933 + 1;
- 268 554 933 ÷ 2 = 134 277 466 + 1;
- 134 277 466 ÷ 2 = 67 138 733 + 0;
- 67 138 733 ÷ 2 = 33 569 366 + 1;
- 33 569 366 ÷ 2 = 16 784 683 + 0;
- 16 784 683 ÷ 2 = 8 392 341 + 1;
- 8 392 341 ÷ 2 = 4 196 170 + 1;
- 4 196 170 ÷ 2 = 2 098 085 + 0;
- 2 098 085 ÷ 2 = 1 049 042 + 1;
- 1 049 042 ÷ 2 = 524 521 + 0;
- 524 521 ÷ 2 = 262 260 + 1;
- 262 260 ÷ 2 = 131 130 + 0;
- 131 130 ÷ 2 = 65 565 + 0;
- 65 565 ÷ 2 = 32 782 + 1;
- 32 782 ÷ 2 = 16 391 + 0;
- 16 391 ÷ 2 = 8 195 + 1;
- 8 195 ÷ 2 = 4 097 + 1;
- 4 097 ÷ 2 = 2 048 + 1;
- 2 048 ÷ 2 = 1 024 + 0;
- 1 024 ÷ 2 = 512 + 0;
- 512 ÷ 2 = 256 + 0;
- 256 ÷ 2 = 128 + 0;
- 128 ÷ 2 = 64 + 0;
- 64 ÷ 2 = 32 + 0;
- 32 ÷ 2 = 16 + 0;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 100 001 009 209(10) = 1 0000 0000 0001 1101 0010 1011 0101 1110 0011 1001(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 41.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 41,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 1 100 001 009 209(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.