1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 073 614 154 ÷ 2 = 536 807 077 + 0;
- 536 807 077 ÷ 2 = 268 403 538 + 1;
- 268 403 538 ÷ 2 = 134 201 769 + 0;
- 134 201 769 ÷ 2 = 67 100 884 + 1;
- 67 100 884 ÷ 2 = 33 550 442 + 0;
- 33 550 442 ÷ 2 = 16 775 221 + 0;
- 16 775 221 ÷ 2 = 8 387 610 + 1;
- 8 387 610 ÷ 2 = 4 193 805 + 0;
- 4 193 805 ÷ 2 = 2 096 902 + 1;
- 2 096 902 ÷ 2 = 1 048 451 + 0;
- 1 048 451 ÷ 2 = 524 225 + 1;
- 524 225 ÷ 2 = 262 112 + 1;
- 262 112 ÷ 2 = 131 056 + 0;
- 131 056 ÷ 2 = 65 528 + 0;
- 65 528 ÷ 2 = 32 764 + 0;
- 32 764 ÷ 2 = 16 382 + 0;
- 16 382 ÷ 2 = 8 191 + 0;
- 8 191 ÷ 2 = 4 095 + 1;
- 4 095 ÷ 2 = 2 047 + 1;
- 2 047 ÷ 2 = 1 023 + 1;
- 1 023 ÷ 2 = 511 + 1;
- 511 ÷ 2 = 255 + 1;
- 255 ÷ 2 = 127 + 1;
- 127 ÷ 2 = 63 + 1;
- 63 ÷ 2 = 31 + 1;
- 31 ÷ 2 = 15 + 1;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 073 614 154(10) = 11 1111 1111 1110 0000 1101 0100 1010(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 30.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 30,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 1 073 614 154(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.