1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 051 650 ÷ 2 = 525 825 + 0;
- 525 825 ÷ 2 = 262 912 + 1;
- 262 912 ÷ 2 = 131 456 + 0;
- 131 456 ÷ 2 = 65 728 + 0;
- 65 728 ÷ 2 = 32 864 + 0;
- 32 864 ÷ 2 = 16 432 + 0;
- 16 432 ÷ 2 = 8 216 + 0;
- 8 216 ÷ 2 = 4 108 + 0;
- 4 108 ÷ 2 = 2 054 + 0;
- 2 054 ÷ 2 = 1 027 + 0;
- 1 027 ÷ 2 = 513 + 1;
- 513 ÷ 2 = 256 + 1;
- 256 ÷ 2 = 128 + 0;
- 128 ÷ 2 = 64 + 0;
- 64 ÷ 2 = 32 + 0;
- 32 ÷ 2 = 16 + 0;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 051 650(10) = 1 0000 0000 1100 0000 0010(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 21.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 21,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 1 051 650(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.