1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 101 111 110 477 ÷ 2 = 50 555 555 238 + 1;
- 50 555 555 238 ÷ 2 = 25 277 777 619 + 0;
- 25 277 777 619 ÷ 2 = 12 638 888 809 + 1;
- 12 638 888 809 ÷ 2 = 6 319 444 404 + 1;
- 6 319 444 404 ÷ 2 = 3 159 722 202 + 0;
- 3 159 722 202 ÷ 2 = 1 579 861 101 + 0;
- 1 579 861 101 ÷ 2 = 789 930 550 + 1;
- 789 930 550 ÷ 2 = 394 965 275 + 0;
- 394 965 275 ÷ 2 = 197 482 637 + 1;
- 197 482 637 ÷ 2 = 98 741 318 + 1;
- 98 741 318 ÷ 2 = 49 370 659 + 0;
- 49 370 659 ÷ 2 = 24 685 329 + 1;
- 24 685 329 ÷ 2 = 12 342 664 + 1;
- 12 342 664 ÷ 2 = 6 171 332 + 0;
- 6 171 332 ÷ 2 = 3 085 666 + 0;
- 3 085 666 ÷ 2 = 1 542 833 + 0;
- 1 542 833 ÷ 2 = 771 416 + 1;
- 771 416 ÷ 2 = 385 708 + 0;
- 385 708 ÷ 2 = 192 854 + 0;
- 192 854 ÷ 2 = 96 427 + 0;
- 96 427 ÷ 2 = 48 213 + 1;
- 48 213 ÷ 2 = 24 106 + 1;
- 24 106 ÷ 2 = 12 053 + 0;
- 12 053 ÷ 2 = 6 026 + 1;
- 6 026 ÷ 2 = 3 013 + 0;
- 3 013 ÷ 2 = 1 506 + 1;
- 1 506 ÷ 2 = 753 + 0;
- 753 ÷ 2 = 376 + 1;
- 376 ÷ 2 = 188 + 0;
- 188 ÷ 2 = 94 + 0;
- 94 ÷ 2 = 47 + 0;
- 47 ÷ 2 = 23 + 1;
- 23 ÷ 2 = 11 + 1;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
101 111 110 477(10) = 1 0111 1000 1010 1011 0001 0001 1011 0100 1101(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 37.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 37,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 101 111 110 477(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.