1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 10 111 101 100 058 ÷ 2 = 5 055 550 550 029 + 0;
- 5 055 550 550 029 ÷ 2 = 2 527 775 275 014 + 1;
- 2 527 775 275 014 ÷ 2 = 1 263 887 637 507 + 0;
- 1 263 887 637 507 ÷ 2 = 631 943 818 753 + 1;
- 631 943 818 753 ÷ 2 = 315 971 909 376 + 1;
- 315 971 909 376 ÷ 2 = 157 985 954 688 + 0;
- 157 985 954 688 ÷ 2 = 78 992 977 344 + 0;
- 78 992 977 344 ÷ 2 = 39 496 488 672 + 0;
- 39 496 488 672 ÷ 2 = 19 748 244 336 + 0;
- 19 748 244 336 ÷ 2 = 9 874 122 168 + 0;
- 9 874 122 168 ÷ 2 = 4 937 061 084 + 0;
- 4 937 061 084 ÷ 2 = 2 468 530 542 + 0;
- 2 468 530 542 ÷ 2 = 1 234 265 271 + 0;
- 1 234 265 271 ÷ 2 = 617 132 635 + 1;
- 617 132 635 ÷ 2 = 308 566 317 + 1;
- 308 566 317 ÷ 2 = 154 283 158 + 1;
- 154 283 158 ÷ 2 = 77 141 579 + 0;
- 77 141 579 ÷ 2 = 38 570 789 + 1;
- 38 570 789 ÷ 2 = 19 285 394 + 1;
- 19 285 394 ÷ 2 = 9 642 697 + 0;
- 9 642 697 ÷ 2 = 4 821 348 + 1;
- 4 821 348 ÷ 2 = 2 410 674 + 0;
- 2 410 674 ÷ 2 = 1 205 337 + 0;
- 1 205 337 ÷ 2 = 602 668 + 1;
- 602 668 ÷ 2 = 301 334 + 0;
- 301 334 ÷ 2 = 150 667 + 0;
- 150 667 ÷ 2 = 75 333 + 1;
- 75 333 ÷ 2 = 37 666 + 1;
- 37 666 ÷ 2 = 18 833 + 0;
- 18 833 ÷ 2 = 9 416 + 1;
- 9 416 ÷ 2 = 4 708 + 0;
- 4 708 ÷ 2 = 2 354 + 0;
- 2 354 ÷ 2 = 1 177 + 0;
- 1 177 ÷ 2 = 588 + 1;
- 588 ÷ 2 = 294 + 0;
- 294 ÷ 2 = 147 + 0;
- 147 ÷ 2 = 73 + 1;
- 73 ÷ 2 = 36 + 1;
- 36 ÷ 2 = 18 + 0;
- 18 ÷ 2 = 9 + 0;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
10 111 101 100 058(10) = 1001 0011 0010 0010 1100 1001 0110 1110 0000 0001 1010(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 44.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 44,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Number 10 111 101 100 058(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
10 111 101 100 058(10) = 0000 0000 0000 0000 0000 1001 0011 0010 0010 1100 1001 0110 1110 0000 0001 1010
Spaces were used to group digits: for binary, by 4, for decimal, by 3.