1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 101 101 111 110 969 ÷ 2 = 50 550 555 555 484 + 1;
- 50 550 555 555 484 ÷ 2 = 25 275 277 777 742 + 0;
- 25 275 277 777 742 ÷ 2 = 12 637 638 888 871 + 0;
- 12 637 638 888 871 ÷ 2 = 6 318 819 444 435 + 1;
- 6 318 819 444 435 ÷ 2 = 3 159 409 722 217 + 1;
- 3 159 409 722 217 ÷ 2 = 1 579 704 861 108 + 1;
- 1 579 704 861 108 ÷ 2 = 789 852 430 554 + 0;
- 789 852 430 554 ÷ 2 = 394 926 215 277 + 0;
- 394 926 215 277 ÷ 2 = 197 463 107 638 + 1;
- 197 463 107 638 ÷ 2 = 98 731 553 819 + 0;
- 98 731 553 819 ÷ 2 = 49 365 776 909 + 1;
- 49 365 776 909 ÷ 2 = 24 682 888 454 + 1;
- 24 682 888 454 ÷ 2 = 12 341 444 227 + 0;
- 12 341 444 227 ÷ 2 = 6 170 722 113 + 1;
- 6 170 722 113 ÷ 2 = 3 085 361 056 + 1;
- 3 085 361 056 ÷ 2 = 1 542 680 528 + 0;
- 1 542 680 528 ÷ 2 = 771 340 264 + 0;
- 771 340 264 ÷ 2 = 385 670 132 + 0;
- 385 670 132 ÷ 2 = 192 835 066 + 0;
- 192 835 066 ÷ 2 = 96 417 533 + 0;
- 96 417 533 ÷ 2 = 48 208 766 + 1;
- 48 208 766 ÷ 2 = 24 104 383 + 0;
- 24 104 383 ÷ 2 = 12 052 191 + 1;
- 12 052 191 ÷ 2 = 6 026 095 + 1;
- 6 026 095 ÷ 2 = 3 013 047 + 1;
- 3 013 047 ÷ 2 = 1 506 523 + 1;
- 1 506 523 ÷ 2 = 753 261 + 1;
- 753 261 ÷ 2 = 376 630 + 1;
- 376 630 ÷ 2 = 188 315 + 0;
- 188 315 ÷ 2 = 94 157 + 1;
- 94 157 ÷ 2 = 47 078 + 1;
- 47 078 ÷ 2 = 23 539 + 0;
- 23 539 ÷ 2 = 11 769 + 1;
- 11 769 ÷ 2 = 5 884 + 1;
- 5 884 ÷ 2 = 2 942 + 0;
- 2 942 ÷ 2 = 1 471 + 0;
- 1 471 ÷ 2 = 735 + 1;
- 735 ÷ 2 = 367 + 1;
- 367 ÷ 2 = 183 + 1;
- 183 ÷ 2 = 91 + 1;
- 91 ÷ 2 = 45 + 1;
- 45 ÷ 2 = 22 + 1;
- 22 ÷ 2 = 11 + 0;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
101 101 111 110 969(10) = 101 1011 1111 0011 0110 1111 1101 0000 0110 1101 0011 1001(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 47.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 47,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Number 101 101 111 110 969(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
101 101 111 110 969(10) = 0000 0000 0000 0000 0101 1011 1111 0011 0110 1111 1101 0000 0110 1101 0011 1001
Spaces were used to group digits: for binary, by 4, for decimal, by 3.