1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 101 100 010 006 ÷ 2 = 50 550 005 003 + 0;
- 50 550 005 003 ÷ 2 = 25 275 002 501 + 1;
- 25 275 002 501 ÷ 2 = 12 637 501 250 + 1;
- 12 637 501 250 ÷ 2 = 6 318 750 625 + 0;
- 6 318 750 625 ÷ 2 = 3 159 375 312 + 1;
- 3 159 375 312 ÷ 2 = 1 579 687 656 + 0;
- 1 579 687 656 ÷ 2 = 789 843 828 + 0;
- 789 843 828 ÷ 2 = 394 921 914 + 0;
- 394 921 914 ÷ 2 = 197 460 957 + 0;
- 197 460 957 ÷ 2 = 98 730 478 + 1;
- 98 730 478 ÷ 2 = 49 365 239 + 0;
- 49 365 239 ÷ 2 = 24 682 619 + 1;
- 24 682 619 ÷ 2 = 12 341 309 + 1;
- 12 341 309 ÷ 2 = 6 170 654 + 1;
- 6 170 654 ÷ 2 = 3 085 327 + 0;
- 3 085 327 ÷ 2 = 1 542 663 + 1;
- 1 542 663 ÷ 2 = 771 331 + 1;
- 771 331 ÷ 2 = 385 665 + 1;
- 385 665 ÷ 2 = 192 832 + 1;
- 192 832 ÷ 2 = 96 416 + 0;
- 96 416 ÷ 2 = 48 208 + 0;
- 48 208 ÷ 2 = 24 104 + 0;
- 24 104 ÷ 2 = 12 052 + 0;
- 12 052 ÷ 2 = 6 026 + 0;
- 6 026 ÷ 2 = 3 013 + 0;
- 3 013 ÷ 2 = 1 506 + 1;
- 1 506 ÷ 2 = 753 + 0;
- 753 ÷ 2 = 376 + 1;
- 376 ÷ 2 = 188 + 0;
- 188 ÷ 2 = 94 + 0;
- 94 ÷ 2 = 47 + 0;
- 47 ÷ 2 = 23 + 1;
- 23 ÷ 2 = 11 + 1;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
101 100 010 006(10) = 1 0111 1000 1010 0000 0111 1011 1010 0001 0110(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 37.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 37,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 101 100 010 006(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.