1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 010 111 100 101 029 ÷ 2 = 505 055 550 050 514 + 1;
- 505 055 550 050 514 ÷ 2 = 252 527 775 025 257 + 0;
- 252 527 775 025 257 ÷ 2 = 126 263 887 512 628 + 1;
- 126 263 887 512 628 ÷ 2 = 63 131 943 756 314 + 0;
- 63 131 943 756 314 ÷ 2 = 31 565 971 878 157 + 0;
- 31 565 971 878 157 ÷ 2 = 15 782 985 939 078 + 1;
- 15 782 985 939 078 ÷ 2 = 7 891 492 969 539 + 0;
- 7 891 492 969 539 ÷ 2 = 3 945 746 484 769 + 1;
- 3 945 746 484 769 ÷ 2 = 1 972 873 242 384 + 1;
- 1 972 873 242 384 ÷ 2 = 986 436 621 192 + 0;
- 986 436 621 192 ÷ 2 = 493 218 310 596 + 0;
- 493 218 310 596 ÷ 2 = 246 609 155 298 + 0;
- 246 609 155 298 ÷ 2 = 123 304 577 649 + 0;
- 123 304 577 649 ÷ 2 = 61 652 288 824 + 1;
- 61 652 288 824 ÷ 2 = 30 826 144 412 + 0;
- 30 826 144 412 ÷ 2 = 15 413 072 206 + 0;
- 15 413 072 206 ÷ 2 = 7 706 536 103 + 0;
- 7 706 536 103 ÷ 2 = 3 853 268 051 + 1;
- 3 853 268 051 ÷ 2 = 1 926 634 025 + 1;
- 1 926 634 025 ÷ 2 = 963 317 012 + 1;
- 963 317 012 ÷ 2 = 481 658 506 + 0;
- 481 658 506 ÷ 2 = 240 829 253 + 0;
- 240 829 253 ÷ 2 = 120 414 626 + 1;
- 120 414 626 ÷ 2 = 60 207 313 + 0;
- 60 207 313 ÷ 2 = 30 103 656 + 1;
- 30 103 656 ÷ 2 = 15 051 828 + 0;
- 15 051 828 ÷ 2 = 7 525 914 + 0;
- 7 525 914 ÷ 2 = 3 762 957 + 0;
- 3 762 957 ÷ 2 = 1 881 478 + 1;
- 1 881 478 ÷ 2 = 940 739 + 0;
- 940 739 ÷ 2 = 470 369 + 1;
- 470 369 ÷ 2 = 235 184 + 1;
- 235 184 ÷ 2 = 117 592 + 0;
- 117 592 ÷ 2 = 58 796 + 0;
- 58 796 ÷ 2 = 29 398 + 0;
- 29 398 ÷ 2 = 14 699 + 0;
- 14 699 ÷ 2 = 7 349 + 1;
- 7 349 ÷ 2 = 3 674 + 1;
- 3 674 ÷ 2 = 1 837 + 0;
- 1 837 ÷ 2 = 918 + 1;
- 918 ÷ 2 = 459 + 0;
- 459 ÷ 2 = 229 + 1;
- 229 ÷ 2 = 114 + 1;
- 114 ÷ 2 = 57 + 0;
- 57 ÷ 2 = 28 + 1;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 010 111 100 101 029(10) = 11 1001 0110 1011 0000 1101 0001 0100 1110 0010 0001 1010 0101(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 1 010 111 100 101 029(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.