1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 101 011 010 100 884 ÷ 2 = 50 505 505 050 442 + 0;
- 50 505 505 050 442 ÷ 2 = 25 252 752 525 221 + 0;
- 25 252 752 525 221 ÷ 2 = 12 626 376 262 610 + 1;
- 12 626 376 262 610 ÷ 2 = 6 313 188 131 305 + 0;
- 6 313 188 131 305 ÷ 2 = 3 156 594 065 652 + 1;
- 3 156 594 065 652 ÷ 2 = 1 578 297 032 826 + 0;
- 1 578 297 032 826 ÷ 2 = 789 148 516 413 + 0;
- 789 148 516 413 ÷ 2 = 394 574 258 206 + 1;
- 394 574 258 206 ÷ 2 = 197 287 129 103 + 0;
- 197 287 129 103 ÷ 2 = 98 643 564 551 + 1;
- 98 643 564 551 ÷ 2 = 49 321 782 275 + 1;
- 49 321 782 275 ÷ 2 = 24 660 891 137 + 1;
- 24 660 891 137 ÷ 2 = 12 330 445 568 + 1;
- 12 330 445 568 ÷ 2 = 6 165 222 784 + 0;
- 6 165 222 784 ÷ 2 = 3 082 611 392 + 0;
- 3 082 611 392 ÷ 2 = 1 541 305 696 + 0;
- 1 541 305 696 ÷ 2 = 770 652 848 + 0;
- 770 652 848 ÷ 2 = 385 326 424 + 0;
- 385 326 424 ÷ 2 = 192 663 212 + 0;
- 192 663 212 ÷ 2 = 96 331 606 + 0;
- 96 331 606 ÷ 2 = 48 165 803 + 0;
- 48 165 803 ÷ 2 = 24 082 901 + 1;
- 24 082 901 ÷ 2 = 12 041 450 + 1;
- 12 041 450 ÷ 2 = 6 020 725 + 0;
- 6 020 725 ÷ 2 = 3 010 362 + 1;
- 3 010 362 ÷ 2 = 1 505 181 + 0;
- 1 505 181 ÷ 2 = 752 590 + 1;
- 752 590 ÷ 2 = 376 295 + 0;
- 376 295 ÷ 2 = 188 147 + 1;
- 188 147 ÷ 2 = 94 073 + 1;
- 94 073 ÷ 2 = 47 036 + 1;
- 47 036 ÷ 2 = 23 518 + 0;
- 23 518 ÷ 2 = 11 759 + 0;
- 11 759 ÷ 2 = 5 879 + 1;
- 5 879 ÷ 2 = 2 939 + 1;
- 2 939 ÷ 2 = 1 469 + 1;
- 1 469 ÷ 2 = 734 + 1;
- 734 ÷ 2 = 367 + 0;
- 367 ÷ 2 = 183 + 1;
- 183 ÷ 2 = 91 + 1;
- 91 ÷ 2 = 45 + 1;
- 45 ÷ 2 = 22 + 1;
- 22 ÷ 2 = 11 + 0;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
101 011 010 100 884(10) = 101 1011 1101 1110 0111 0101 0110 0000 0001 1110 1001 0100(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 47.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 47,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 101 011 010 100 884(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.