1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 10 101 001 555 558 ÷ 2 = 5 050 500 777 779 + 0;
- 5 050 500 777 779 ÷ 2 = 2 525 250 388 889 + 1;
- 2 525 250 388 889 ÷ 2 = 1 262 625 194 444 + 1;
- 1 262 625 194 444 ÷ 2 = 631 312 597 222 + 0;
- 631 312 597 222 ÷ 2 = 315 656 298 611 + 0;
- 315 656 298 611 ÷ 2 = 157 828 149 305 + 1;
- 157 828 149 305 ÷ 2 = 78 914 074 652 + 1;
- 78 914 074 652 ÷ 2 = 39 457 037 326 + 0;
- 39 457 037 326 ÷ 2 = 19 728 518 663 + 0;
- 19 728 518 663 ÷ 2 = 9 864 259 331 + 1;
- 9 864 259 331 ÷ 2 = 4 932 129 665 + 1;
- 4 932 129 665 ÷ 2 = 2 466 064 832 + 1;
- 2 466 064 832 ÷ 2 = 1 233 032 416 + 0;
- 1 233 032 416 ÷ 2 = 616 516 208 + 0;
- 616 516 208 ÷ 2 = 308 258 104 + 0;
- 308 258 104 ÷ 2 = 154 129 052 + 0;
- 154 129 052 ÷ 2 = 77 064 526 + 0;
- 77 064 526 ÷ 2 = 38 532 263 + 0;
- 38 532 263 ÷ 2 = 19 266 131 + 1;
- 19 266 131 ÷ 2 = 9 633 065 + 1;
- 9 633 065 ÷ 2 = 4 816 532 + 1;
- 4 816 532 ÷ 2 = 2 408 266 + 0;
- 2 408 266 ÷ 2 = 1 204 133 + 0;
- 1 204 133 ÷ 2 = 602 066 + 1;
- 602 066 ÷ 2 = 301 033 + 0;
- 301 033 ÷ 2 = 150 516 + 1;
- 150 516 ÷ 2 = 75 258 + 0;
- 75 258 ÷ 2 = 37 629 + 0;
- 37 629 ÷ 2 = 18 814 + 1;
- 18 814 ÷ 2 = 9 407 + 0;
- 9 407 ÷ 2 = 4 703 + 1;
- 4 703 ÷ 2 = 2 351 + 1;
- 2 351 ÷ 2 = 1 175 + 1;
- 1 175 ÷ 2 = 587 + 1;
- 587 ÷ 2 = 293 + 1;
- 293 ÷ 2 = 146 + 1;
- 146 ÷ 2 = 73 + 0;
- 73 ÷ 2 = 36 + 1;
- 36 ÷ 2 = 18 + 0;
- 18 ÷ 2 = 9 + 0;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
10 101 001 555 558(10) = 1001 0010 1111 1101 0010 1001 1100 0000 1110 0110 0110(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 44.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 44,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 10 101 001 555 558(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.