1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 010 011 011 100 057 ÷ 2 = 505 005 505 550 028 + 1;
- 505 005 505 550 028 ÷ 2 = 252 502 752 775 014 + 0;
- 252 502 752 775 014 ÷ 2 = 126 251 376 387 507 + 0;
- 126 251 376 387 507 ÷ 2 = 63 125 688 193 753 + 1;
- 63 125 688 193 753 ÷ 2 = 31 562 844 096 876 + 1;
- 31 562 844 096 876 ÷ 2 = 15 781 422 048 438 + 0;
- 15 781 422 048 438 ÷ 2 = 7 890 711 024 219 + 0;
- 7 890 711 024 219 ÷ 2 = 3 945 355 512 109 + 1;
- 3 945 355 512 109 ÷ 2 = 1 972 677 756 054 + 1;
- 1 972 677 756 054 ÷ 2 = 986 338 878 027 + 0;
- 986 338 878 027 ÷ 2 = 493 169 439 013 + 1;
- 493 169 439 013 ÷ 2 = 246 584 719 506 + 1;
- 246 584 719 506 ÷ 2 = 123 292 359 753 + 0;
- 123 292 359 753 ÷ 2 = 61 646 179 876 + 1;
- 61 646 179 876 ÷ 2 = 30 823 089 938 + 0;
- 30 823 089 938 ÷ 2 = 15 411 544 969 + 0;
- 15 411 544 969 ÷ 2 = 7 705 772 484 + 1;
- 7 705 772 484 ÷ 2 = 3 852 886 242 + 0;
- 3 852 886 242 ÷ 2 = 1 926 443 121 + 0;
- 1 926 443 121 ÷ 2 = 963 221 560 + 1;
- 963 221 560 ÷ 2 = 481 610 780 + 0;
- 481 610 780 ÷ 2 = 240 805 390 + 0;
- 240 805 390 ÷ 2 = 120 402 695 + 0;
- 120 402 695 ÷ 2 = 60 201 347 + 1;
- 60 201 347 ÷ 2 = 30 100 673 + 1;
- 30 100 673 ÷ 2 = 15 050 336 + 1;
- 15 050 336 ÷ 2 = 7 525 168 + 0;
- 7 525 168 ÷ 2 = 3 762 584 + 0;
- 3 762 584 ÷ 2 = 1 881 292 + 0;
- 1 881 292 ÷ 2 = 940 646 + 0;
- 940 646 ÷ 2 = 470 323 + 0;
- 470 323 ÷ 2 = 235 161 + 1;
- 235 161 ÷ 2 = 117 580 + 1;
- 117 580 ÷ 2 = 58 790 + 0;
- 58 790 ÷ 2 = 29 395 + 0;
- 29 395 ÷ 2 = 14 697 + 1;
- 14 697 ÷ 2 = 7 348 + 1;
- 7 348 ÷ 2 = 3 674 + 0;
- 3 674 ÷ 2 = 1 837 + 0;
- 1 837 ÷ 2 = 918 + 1;
- 918 ÷ 2 = 459 + 0;
- 459 ÷ 2 = 229 + 1;
- 229 ÷ 2 = 114 + 1;
- 114 ÷ 2 = 57 + 0;
- 57 ÷ 2 = 28 + 1;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 010 011 011 100 057(10) = 11 1001 0110 1001 1001 1000 0011 1000 1001 0010 1101 1001 1001(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 1 010 011 011 100 057(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.