1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 001 101 101 111 103 ÷ 2 = 500 550 550 555 551 + 1;
- 500 550 550 555 551 ÷ 2 = 250 275 275 277 775 + 1;
- 250 275 275 277 775 ÷ 2 = 125 137 637 638 887 + 1;
- 125 137 637 638 887 ÷ 2 = 62 568 818 819 443 + 1;
- 62 568 818 819 443 ÷ 2 = 31 284 409 409 721 + 1;
- 31 284 409 409 721 ÷ 2 = 15 642 204 704 860 + 1;
- 15 642 204 704 860 ÷ 2 = 7 821 102 352 430 + 0;
- 7 821 102 352 430 ÷ 2 = 3 910 551 176 215 + 0;
- 3 910 551 176 215 ÷ 2 = 1 955 275 588 107 + 1;
- 1 955 275 588 107 ÷ 2 = 977 637 794 053 + 1;
- 977 637 794 053 ÷ 2 = 488 818 897 026 + 1;
- 488 818 897 026 ÷ 2 = 244 409 448 513 + 0;
- 244 409 448 513 ÷ 2 = 122 204 724 256 + 1;
- 122 204 724 256 ÷ 2 = 61 102 362 128 + 0;
- 61 102 362 128 ÷ 2 = 30 551 181 064 + 0;
- 30 551 181 064 ÷ 2 = 15 275 590 532 + 0;
- 15 275 590 532 ÷ 2 = 7 637 795 266 + 0;
- 7 637 795 266 ÷ 2 = 3 818 897 633 + 0;
- 3 818 897 633 ÷ 2 = 1 909 448 816 + 1;
- 1 909 448 816 ÷ 2 = 954 724 408 + 0;
- 954 724 408 ÷ 2 = 477 362 204 + 0;
- 477 362 204 ÷ 2 = 238 681 102 + 0;
- 238 681 102 ÷ 2 = 119 340 551 + 0;
- 119 340 551 ÷ 2 = 59 670 275 + 1;
- 59 670 275 ÷ 2 = 29 835 137 + 1;
- 29 835 137 ÷ 2 = 14 917 568 + 1;
- 14 917 568 ÷ 2 = 7 458 784 + 0;
- 7 458 784 ÷ 2 = 3 729 392 + 0;
- 3 729 392 ÷ 2 = 1 864 696 + 0;
- 1 864 696 ÷ 2 = 932 348 + 0;
- 932 348 ÷ 2 = 466 174 + 0;
- 466 174 ÷ 2 = 233 087 + 0;
- 233 087 ÷ 2 = 116 543 + 1;
- 116 543 ÷ 2 = 58 271 + 1;
- 58 271 ÷ 2 = 29 135 + 1;
- 29 135 ÷ 2 = 14 567 + 1;
- 14 567 ÷ 2 = 7 283 + 1;
- 7 283 ÷ 2 = 3 641 + 1;
- 3 641 ÷ 2 = 1 820 + 1;
- 1 820 ÷ 2 = 910 + 0;
- 910 ÷ 2 = 455 + 0;
- 455 ÷ 2 = 227 + 1;
- 227 ÷ 2 = 113 + 1;
- 113 ÷ 2 = 56 + 1;
- 56 ÷ 2 = 28 + 0;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 001 101 101 111 103(10) = 11 1000 1110 0111 1111 0000 0011 1000 0100 0001 0111 0011 1111(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 1 001 101 101 111 103(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.