1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 001 011 011 110 045 ÷ 2 = 500 505 505 555 022 + 1;
- 500 505 505 555 022 ÷ 2 = 250 252 752 777 511 + 0;
- 250 252 752 777 511 ÷ 2 = 125 126 376 388 755 + 1;
- 125 126 376 388 755 ÷ 2 = 62 563 188 194 377 + 1;
- 62 563 188 194 377 ÷ 2 = 31 281 594 097 188 + 1;
- 31 281 594 097 188 ÷ 2 = 15 640 797 048 594 + 0;
- 15 640 797 048 594 ÷ 2 = 7 820 398 524 297 + 0;
- 7 820 398 524 297 ÷ 2 = 3 910 199 262 148 + 1;
- 3 910 199 262 148 ÷ 2 = 1 955 099 631 074 + 0;
- 1 955 099 631 074 ÷ 2 = 977 549 815 537 + 0;
- 977 549 815 537 ÷ 2 = 488 774 907 768 + 1;
- 488 774 907 768 ÷ 2 = 244 387 453 884 + 0;
- 244 387 453 884 ÷ 2 = 122 193 726 942 + 0;
- 122 193 726 942 ÷ 2 = 61 096 863 471 + 0;
- 61 096 863 471 ÷ 2 = 30 548 431 735 + 1;
- 30 548 431 735 ÷ 2 = 15 274 215 867 + 1;
- 15 274 215 867 ÷ 2 = 7 637 107 933 + 1;
- 7 637 107 933 ÷ 2 = 3 818 553 966 + 1;
- 3 818 553 966 ÷ 2 = 1 909 276 983 + 0;
- 1 909 276 983 ÷ 2 = 954 638 491 + 1;
- 954 638 491 ÷ 2 = 477 319 245 + 1;
- 477 319 245 ÷ 2 = 238 659 622 + 1;
- 238 659 622 ÷ 2 = 119 329 811 + 0;
- 119 329 811 ÷ 2 = 59 664 905 + 1;
- 59 664 905 ÷ 2 = 29 832 452 + 1;
- 29 832 452 ÷ 2 = 14 916 226 + 0;
- 14 916 226 ÷ 2 = 7 458 113 + 0;
- 7 458 113 ÷ 2 = 3 729 056 + 1;
- 3 729 056 ÷ 2 = 1 864 528 + 0;
- 1 864 528 ÷ 2 = 932 264 + 0;
- 932 264 ÷ 2 = 466 132 + 0;
- 466 132 ÷ 2 = 233 066 + 0;
- 233 066 ÷ 2 = 116 533 + 0;
- 116 533 ÷ 2 = 58 266 + 1;
- 58 266 ÷ 2 = 29 133 + 0;
- 29 133 ÷ 2 = 14 566 + 1;
- 14 566 ÷ 2 = 7 283 + 0;
- 7 283 ÷ 2 = 3 641 + 1;
- 3 641 ÷ 2 = 1 820 + 1;
- 1 820 ÷ 2 = 910 + 0;
- 910 ÷ 2 = 455 + 0;
- 455 ÷ 2 = 227 + 1;
- 227 ÷ 2 = 113 + 1;
- 113 ÷ 2 = 56 + 1;
- 56 ÷ 2 = 28 + 0;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 001 011 011 110 045(10) = 11 1000 1110 0110 1010 0000 1001 1011 1011 1100 0100 1001 1101(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 1 001 011 011 110 045(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.