1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 001 010 000 010 320 ÷ 2 = 500 505 000 005 160 + 0;
- 500 505 000 005 160 ÷ 2 = 250 252 500 002 580 + 0;
- 250 252 500 002 580 ÷ 2 = 125 126 250 001 290 + 0;
- 125 126 250 001 290 ÷ 2 = 62 563 125 000 645 + 0;
- 62 563 125 000 645 ÷ 2 = 31 281 562 500 322 + 1;
- 31 281 562 500 322 ÷ 2 = 15 640 781 250 161 + 0;
- 15 640 781 250 161 ÷ 2 = 7 820 390 625 080 + 1;
- 7 820 390 625 080 ÷ 2 = 3 910 195 312 540 + 0;
- 3 910 195 312 540 ÷ 2 = 1 955 097 656 270 + 0;
- 1 955 097 656 270 ÷ 2 = 977 548 828 135 + 0;
- 977 548 828 135 ÷ 2 = 488 774 414 067 + 1;
- 488 774 414 067 ÷ 2 = 244 387 207 033 + 1;
- 244 387 207 033 ÷ 2 = 122 193 603 516 + 1;
- 122 193 603 516 ÷ 2 = 61 096 801 758 + 0;
- 61 096 801 758 ÷ 2 = 30 548 400 879 + 0;
- 30 548 400 879 ÷ 2 = 15 274 200 439 + 1;
- 15 274 200 439 ÷ 2 = 7 637 100 219 + 1;
- 7 637 100 219 ÷ 2 = 3 818 550 109 + 1;
- 3 818 550 109 ÷ 2 = 1 909 275 054 + 1;
- 1 909 275 054 ÷ 2 = 954 637 527 + 0;
- 954 637 527 ÷ 2 = 477 318 763 + 1;
- 477 318 763 ÷ 2 = 238 659 381 + 1;
- 238 659 381 ÷ 2 = 119 329 690 + 1;
- 119 329 690 ÷ 2 = 59 664 845 + 0;
- 59 664 845 ÷ 2 = 29 832 422 + 1;
- 29 832 422 ÷ 2 = 14 916 211 + 0;
- 14 916 211 ÷ 2 = 7 458 105 + 1;
- 7 458 105 ÷ 2 = 3 729 052 + 1;
- 3 729 052 ÷ 2 = 1 864 526 + 0;
- 1 864 526 ÷ 2 = 932 263 + 0;
- 932 263 ÷ 2 = 466 131 + 1;
- 466 131 ÷ 2 = 233 065 + 1;
- 233 065 ÷ 2 = 116 532 + 1;
- 116 532 ÷ 2 = 58 266 + 0;
- 58 266 ÷ 2 = 29 133 + 0;
- 29 133 ÷ 2 = 14 566 + 1;
- 14 566 ÷ 2 = 7 283 + 0;
- 7 283 ÷ 2 = 3 641 + 1;
- 3 641 ÷ 2 = 1 820 + 1;
- 1 820 ÷ 2 = 910 + 0;
- 910 ÷ 2 = 455 + 0;
- 455 ÷ 2 = 227 + 1;
- 227 ÷ 2 = 113 + 1;
- 113 ÷ 2 = 56 + 1;
- 56 ÷ 2 = 28 + 0;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 001 010 000 010 320(10) = 11 1000 1110 0110 1001 1100 1101 0111 0111 1001 1100 0101 0000(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 1 001 010 000 010 320(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.