1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 100 011 011 110 149 ÷ 2 = 50 005 505 555 074 + 1;
- 50 005 505 555 074 ÷ 2 = 25 002 752 777 537 + 0;
- 25 002 752 777 537 ÷ 2 = 12 501 376 388 768 + 1;
- 12 501 376 388 768 ÷ 2 = 6 250 688 194 384 + 0;
- 6 250 688 194 384 ÷ 2 = 3 125 344 097 192 + 0;
- 3 125 344 097 192 ÷ 2 = 1 562 672 048 596 + 0;
- 1 562 672 048 596 ÷ 2 = 781 336 024 298 + 0;
- 781 336 024 298 ÷ 2 = 390 668 012 149 + 0;
- 390 668 012 149 ÷ 2 = 195 334 006 074 + 1;
- 195 334 006 074 ÷ 2 = 97 667 003 037 + 0;
- 97 667 003 037 ÷ 2 = 48 833 501 518 + 1;
- 48 833 501 518 ÷ 2 = 24 416 750 759 + 0;
- 24 416 750 759 ÷ 2 = 12 208 375 379 + 1;
- 12 208 375 379 ÷ 2 = 6 104 187 689 + 1;
- 6 104 187 689 ÷ 2 = 3 052 093 844 + 1;
- 3 052 093 844 ÷ 2 = 1 526 046 922 + 0;
- 1 526 046 922 ÷ 2 = 763 023 461 + 0;
- 763 023 461 ÷ 2 = 381 511 730 + 1;
- 381 511 730 ÷ 2 = 190 755 865 + 0;
- 190 755 865 ÷ 2 = 95 377 932 + 1;
- 95 377 932 ÷ 2 = 47 688 966 + 0;
- 47 688 966 ÷ 2 = 23 844 483 + 0;
- 23 844 483 ÷ 2 = 11 922 241 + 1;
- 11 922 241 ÷ 2 = 5 961 120 + 1;
- 5 961 120 ÷ 2 = 2 980 560 + 0;
- 2 980 560 ÷ 2 = 1 490 280 + 0;
- 1 490 280 ÷ 2 = 745 140 + 0;
- 745 140 ÷ 2 = 372 570 + 0;
- 372 570 ÷ 2 = 186 285 + 0;
- 186 285 ÷ 2 = 93 142 + 1;
- 93 142 ÷ 2 = 46 571 + 0;
- 46 571 ÷ 2 = 23 285 + 1;
- 23 285 ÷ 2 = 11 642 + 1;
- 11 642 ÷ 2 = 5 821 + 0;
- 5 821 ÷ 2 = 2 910 + 1;
- 2 910 ÷ 2 = 1 455 + 0;
- 1 455 ÷ 2 = 727 + 1;
- 727 ÷ 2 = 363 + 1;
- 363 ÷ 2 = 181 + 1;
- 181 ÷ 2 = 90 + 1;
- 90 ÷ 2 = 45 + 0;
- 45 ÷ 2 = 22 + 1;
- 22 ÷ 2 = 11 + 0;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
100 011 011 110 149(10) = 101 1010 1111 0101 1010 0000 1100 1010 0111 0101 0000 0101(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 47.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 47,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Number 100 011 011 110 149(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
100 011 011 110 149(10) = 0000 0000 0000 0000 0101 1010 1111 0101 1010 0000 1100 1010 0111 0101 0000 0101
Spaces were used to group digits: for binary, by 4, for decimal, by 3.