1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 3 249 536 521 ÷ 2 = 1 624 768 260 + 1;
- 1 624 768 260 ÷ 2 = 812 384 130 + 0;
- 812 384 130 ÷ 2 = 406 192 065 + 0;
- 406 192 065 ÷ 2 = 203 096 032 + 1;
- 203 096 032 ÷ 2 = 101 548 016 + 0;
- 101 548 016 ÷ 2 = 50 774 008 + 0;
- 50 774 008 ÷ 2 = 25 387 004 + 0;
- 25 387 004 ÷ 2 = 12 693 502 + 0;
- 12 693 502 ÷ 2 = 6 346 751 + 0;
- 6 346 751 ÷ 2 = 3 173 375 + 1;
- 3 173 375 ÷ 2 = 1 586 687 + 1;
- 1 586 687 ÷ 2 = 793 343 + 1;
- 793 343 ÷ 2 = 396 671 + 1;
- 396 671 ÷ 2 = 198 335 + 1;
- 198 335 ÷ 2 = 99 167 + 1;
- 99 167 ÷ 2 = 49 583 + 1;
- 49 583 ÷ 2 = 24 791 + 1;
- 24 791 ÷ 2 = 12 395 + 1;
- 12 395 ÷ 2 = 6 197 + 1;
- 6 197 ÷ 2 = 3 098 + 1;
- 3 098 ÷ 2 = 1 549 + 0;
- 1 549 ÷ 2 = 774 + 1;
- 774 ÷ 2 = 387 + 0;
- 387 ÷ 2 = 193 + 1;
- 193 ÷ 2 = 96 + 1;
- 96 ÷ 2 = 48 + 0;
- 48 ÷ 2 = 24 + 0;
- 24 ÷ 2 = 12 + 0;
- 12 ÷ 2 = 6 + 0;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
3 249 536 521(10) = 1100 0001 1010 1111 1111 1110 0000 1001(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 32.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 32,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 3 249 536 521(10) converted to signed binary in one's complement representation: