1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 2 782 928 897 ÷ 2 = 1 391 464 448 + 1;
- 1 391 464 448 ÷ 2 = 695 732 224 + 0;
- 695 732 224 ÷ 2 = 347 866 112 + 0;
- 347 866 112 ÷ 2 = 173 933 056 + 0;
- 173 933 056 ÷ 2 = 86 966 528 + 0;
- 86 966 528 ÷ 2 = 43 483 264 + 0;
- 43 483 264 ÷ 2 = 21 741 632 + 0;
- 21 741 632 ÷ 2 = 10 870 816 + 0;
- 10 870 816 ÷ 2 = 5 435 408 + 0;
- 5 435 408 ÷ 2 = 2 717 704 + 0;
- 2 717 704 ÷ 2 = 1 358 852 + 0;
- 1 358 852 ÷ 2 = 679 426 + 0;
- 679 426 ÷ 2 = 339 713 + 0;
- 339 713 ÷ 2 = 169 856 + 1;
- 169 856 ÷ 2 = 84 928 + 0;
- 84 928 ÷ 2 = 42 464 + 0;
- 42 464 ÷ 2 = 21 232 + 0;
- 21 232 ÷ 2 = 10 616 + 0;
- 10 616 ÷ 2 = 5 308 + 0;
- 5 308 ÷ 2 = 2 654 + 0;
- 2 654 ÷ 2 = 1 327 + 0;
- 1 327 ÷ 2 = 663 + 1;
- 663 ÷ 2 = 331 + 1;
- 331 ÷ 2 = 165 + 1;
- 165 ÷ 2 = 82 + 1;
- 82 ÷ 2 = 41 + 0;
- 41 ÷ 2 = 20 + 1;
- 20 ÷ 2 = 10 + 0;
- 10 ÷ 2 = 5 + 0;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
2 782 928 897(10) = 1010 0101 1110 0000 0010 0000 0000 0001(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 32.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 32,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Number 2 782 928 897(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in one's complement representation:
2 782 928 897(10) = 0000 0000 0000 0000 0000 0000 0000 0000 1010 0101 1110 0000 0010 0000 0000 0001
Spaces were used to group digits: for binary, by 4, for decimal, by 3.