1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 869 983 342 ÷ 2 = 934 991 671 + 0;
- 934 991 671 ÷ 2 = 467 495 835 + 1;
- 467 495 835 ÷ 2 = 233 747 917 + 1;
- 233 747 917 ÷ 2 = 116 873 958 + 1;
- 116 873 958 ÷ 2 = 58 436 979 + 0;
- 58 436 979 ÷ 2 = 29 218 489 + 1;
- 29 218 489 ÷ 2 = 14 609 244 + 1;
- 14 609 244 ÷ 2 = 7 304 622 + 0;
- 7 304 622 ÷ 2 = 3 652 311 + 0;
- 3 652 311 ÷ 2 = 1 826 155 + 1;
- 1 826 155 ÷ 2 = 913 077 + 1;
- 913 077 ÷ 2 = 456 538 + 1;
- 456 538 ÷ 2 = 228 269 + 0;
- 228 269 ÷ 2 = 114 134 + 1;
- 114 134 ÷ 2 = 57 067 + 0;
- 57 067 ÷ 2 = 28 533 + 1;
- 28 533 ÷ 2 = 14 266 + 1;
- 14 266 ÷ 2 = 7 133 + 0;
- 7 133 ÷ 2 = 3 566 + 1;
- 3 566 ÷ 2 = 1 783 + 0;
- 1 783 ÷ 2 = 891 + 1;
- 891 ÷ 2 = 445 + 1;
- 445 ÷ 2 = 222 + 1;
- 222 ÷ 2 = 111 + 0;
- 111 ÷ 2 = 55 + 1;
- 55 ÷ 2 = 27 + 1;
- 27 ÷ 2 = 13 + 1;
- 13 ÷ 2 = 6 + 1;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 869 983 342(10) = 110 1111 0111 0101 1010 1110 0110 1110(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Number 1 869 983 342(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in one's complement representation:
1 869 983 342(10) = 0110 1111 0111 0101 1010 1110 0110 1110
Spaces were used to group digits: for binary, by 4, for decimal, by 3.