1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 112 425 951 ÷ 2 = 556 212 975 + 1;
- 556 212 975 ÷ 2 = 278 106 487 + 1;
- 278 106 487 ÷ 2 = 139 053 243 + 1;
- 139 053 243 ÷ 2 = 69 526 621 + 1;
- 69 526 621 ÷ 2 = 34 763 310 + 1;
- 34 763 310 ÷ 2 = 17 381 655 + 0;
- 17 381 655 ÷ 2 = 8 690 827 + 1;
- 8 690 827 ÷ 2 = 4 345 413 + 1;
- 4 345 413 ÷ 2 = 2 172 706 + 1;
- 2 172 706 ÷ 2 = 1 086 353 + 0;
- 1 086 353 ÷ 2 = 543 176 + 1;
- 543 176 ÷ 2 = 271 588 + 0;
- 271 588 ÷ 2 = 135 794 + 0;
- 135 794 ÷ 2 = 67 897 + 0;
- 67 897 ÷ 2 = 33 948 + 1;
- 33 948 ÷ 2 = 16 974 + 0;
- 16 974 ÷ 2 = 8 487 + 0;
- 8 487 ÷ 2 = 4 243 + 1;
- 4 243 ÷ 2 = 2 121 + 1;
- 2 121 ÷ 2 = 1 060 + 1;
- 1 060 ÷ 2 = 530 + 0;
- 530 ÷ 2 = 265 + 0;
- 265 ÷ 2 = 132 + 1;
- 132 ÷ 2 = 66 + 0;
- 66 ÷ 2 = 33 + 0;
- 33 ÷ 2 = 16 + 1;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 112 425 951(10) = 100 0010 0100 1110 0100 0101 1101 1111(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 1 112 425 951(10) converted to signed binary in one's complement representation: