1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 110 011 698 ÷ 2 = 555 005 849 + 0;
- 555 005 849 ÷ 2 = 277 502 924 + 1;
- 277 502 924 ÷ 2 = 138 751 462 + 0;
- 138 751 462 ÷ 2 = 69 375 731 + 0;
- 69 375 731 ÷ 2 = 34 687 865 + 1;
- 34 687 865 ÷ 2 = 17 343 932 + 1;
- 17 343 932 ÷ 2 = 8 671 966 + 0;
- 8 671 966 ÷ 2 = 4 335 983 + 0;
- 4 335 983 ÷ 2 = 2 167 991 + 1;
- 2 167 991 ÷ 2 = 1 083 995 + 1;
- 1 083 995 ÷ 2 = 541 997 + 1;
- 541 997 ÷ 2 = 270 998 + 1;
- 270 998 ÷ 2 = 135 499 + 0;
- 135 499 ÷ 2 = 67 749 + 1;
- 67 749 ÷ 2 = 33 874 + 1;
- 33 874 ÷ 2 = 16 937 + 0;
- 16 937 ÷ 2 = 8 468 + 1;
- 8 468 ÷ 2 = 4 234 + 0;
- 4 234 ÷ 2 = 2 117 + 0;
- 2 117 ÷ 2 = 1 058 + 1;
- 1 058 ÷ 2 = 529 + 0;
- 529 ÷ 2 = 264 + 1;
- 264 ÷ 2 = 132 + 0;
- 132 ÷ 2 = 66 + 0;
- 66 ÷ 2 = 33 + 0;
- 33 ÷ 2 = 16 + 1;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 110 011 698(10) = 100 0010 0010 1001 0110 1111 0011 0010(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 1 110 011 698(10) converted to signed binary in one's complement representation: