1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 100 100 053 ÷ 2 = 550 050 026 + 1;
- 550 050 026 ÷ 2 = 275 025 013 + 0;
- 275 025 013 ÷ 2 = 137 512 506 + 1;
- 137 512 506 ÷ 2 = 68 756 253 + 0;
- 68 756 253 ÷ 2 = 34 378 126 + 1;
- 34 378 126 ÷ 2 = 17 189 063 + 0;
- 17 189 063 ÷ 2 = 8 594 531 + 1;
- 8 594 531 ÷ 2 = 4 297 265 + 1;
- 4 297 265 ÷ 2 = 2 148 632 + 1;
- 2 148 632 ÷ 2 = 1 074 316 + 0;
- 1 074 316 ÷ 2 = 537 158 + 0;
- 537 158 ÷ 2 = 268 579 + 0;
- 268 579 ÷ 2 = 134 289 + 1;
- 134 289 ÷ 2 = 67 144 + 1;
- 67 144 ÷ 2 = 33 572 + 0;
- 33 572 ÷ 2 = 16 786 + 0;
- 16 786 ÷ 2 = 8 393 + 0;
- 8 393 ÷ 2 = 4 196 + 1;
- 4 196 ÷ 2 = 2 098 + 0;
- 2 098 ÷ 2 = 1 049 + 0;
- 1 049 ÷ 2 = 524 + 1;
- 524 ÷ 2 = 262 + 0;
- 262 ÷ 2 = 131 + 0;
- 131 ÷ 2 = 65 + 1;
- 65 ÷ 2 = 32 + 1;
- 32 ÷ 2 = 16 + 0;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 100 100 053(10) = 100 0001 1001 0010 0011 0001 1101 0101(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 1 100 100 053(10) converted to signed binary in one's complement representation: