1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 079 574 495 ÷ 2 = 539 787 247 + 1;
- 539 787 247 ÷ 2 = 269 893 623 + 1;
- 269 893 623 ÷ 2 = 134 946 811 + 1;
- 134 946 811 ÷ 2 = 67 473 405 + 1;
- 67 473 405 ÷ 2 = 33 736 702 + 1;
- 33 736 702 ÷ 2 = 16 868 351 + 0;
- 16 868 351 ÷ 2 = 8 434 175 + 1;
- 8 434 175 ÷ 2 = 4 217 087 + 1;
- 4 217 087 ÷ 2 = 2 108 543 + 1;
- 2 108 543 ÷ 2 = 1 054 271 + 1;
- 1 054 271 ÷ 2 = 527 135 + 1;
- 527 135 ÷ 2 = 263 567 + 1;
- 263 567 ÷ 2 = 131 783 + 1;
- 131 783 ÷ 2 = 65 891 + 1;
- 65 891 ÷ 2 = 32 945 + 1;
- 32 945 ÷ 2 = 16 472 + 1;
- 16 472 ÷ 2 = 8 236 + 0;
- 8 236 ÷ 2 = 4 118 + 0;
- 4 118 ÷ 2 = 2 059 + 0;
- 2 059 ÷ 2 = 1 029 + 1;
- 1 029 ÷ 2 = 514 + 1;
- 514 ÷ 2 = 257 + 0;
- 257 ÷ 2 = 128 + 1;
- 128 ÷ 2 = 64 + 0;
- 64 ÷ 2 = 32 + 0;
- 32 ÷ 2 = 16 + 0;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 079 574 495(10) = 100 0000 0101 1000 1111 1111 1101 1111(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 1 079 574 495(10) converted to signed binary in one's complement representation: