1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 011 111 010 100 129 ÷ 2 = 505 555 505 050 064 + 1;
- 505 555 505 050 064 ÷ 2 = 252 777 752 525 032 + 0;
- 252 777 752 525 032 ÷ 2 = 126 388 876 262 516 + 0;
- 126 388 876 262 516 ÷ 2 = 63 194 438 131 258 + 0;
- 63 194 438 131 258 ÷ 2 = 31 597 219 065 629 + 0;
- 31 597 219 065 629 ÷ 2 = 15 798 609 532 814 + 1;
- 15 798 609 532 814 ÷ 2 = 7 899 304 766 407 + 0;
- 7 899 304 766 407 ÷ 2 = 3 949 652 383 203 + 1;
- 3 949 652 383 203 ÷ 2 = 1 974 826 191 601 + 1;
- 1 974 826 191 601 ÷ 2 = 987 413 095 800 + 1;
- 987 413 095 800 ÷ 2 = 493 706 547 900 + 0;
- 493 706 547 900 ÷ 2 = 246 853 273 950 + 0;
- 246 853 273 950 ÷ 2 = 123 426 636 975 + 0;
- 123 426 636 975 ÷ 2 = 61 713 318 487 + 1;
- 61 713 318 487 ÷ 2 = 30 856 659 243 + 1;
- 30 856 659 243 ÷ 2 = 15 428 329 621 + 1;
- 15 428 329 621 ÷ 2 = 7 714 164 810 + 1;
- 7 714 164 810 ÷ 2 = 3 857 082 405 + 0;
- 3 857 082 405 ÷ 2 = 1 928 541 202 + 1;
- 1 928 541 202 ÷ 2 = 964 270 601 + 0;
- 964 270 601 ÷ 2 = 482 135 300 + 1;
- 482 135 300 ÷ 2 = 241 067 650 + 0;
- 241 067 650 ÷ 2 = 120 533 825 + 0;
- 120 533 825 ÷ 2 = 60 266 912 + 1;
- 60 266 912 ÷ 2 = 30 133 456 + 0;
- 30 133 456 ÷ 2 = 15 066 728 + 0;
- 15 066 728 ÷ 2 = 7 533 364 + 0;
- 7 533 364 ÷ 2 = 3 766 682 + 0;
- 3 766 682 ÷ 2 = 1 883 341 + 0;
- 1 883 341 ÷ 2 = 941 670 + 1;
- 941 670 ÷ 2 = 470 835 + 0;
- 470 835 ÷ 2 = 235 417 + 1;
- 235 417 ÷ 2 = 117 708 + 1;
- 117 708 ÷ 2 = 58 854 + 0;
- 58 854 ÷ 2 = 29 427 + 0;
- 29 427 ÷ 2 = 14 713 + 1;
- 14 713 ÷ 2 = 7 356 + 1;
- 7 356 ÷ 2 = 3 678 + 0;
- 3 678 ÷ 2 = 1 839 + 0;
- 1 839 ÷ 2 = 919 + 1;
- 919 ÷ 2 = 459 + 1;
- 459 ÷ 2 = 229 + 1;
- 229 ÷ 2 = 114 + 1;
- 114 ÷ 2 = 57 + 0;
- 57 ÷ 2 = 28 + 1;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 011 111 010 100 129(10) = 11 1001 0111 1001 1001 1010 0000 1001 0101 1110 0011 1010 0001(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Number 1 011 111 010 100 129(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in one's complement representation:
1 011 111 010 100 129(10) = 0000 0000 0000 0011 1001 0111 1001 1001 1010 0000 1001 0101 1110 0011 1010 0001
Spaces were used to group digits: for binary, by 4, for decimal, by 3.