1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 011 009 851 ÷ 2 = 505 504 925 + 1;
- 505 504 925 ÷ 2 = 252 752 462 + 1;
- 252 752 462 ÷ 2 = 126 376 231 + 0;
- 126 376 231 ÷ 2 = 63 188 115 + 1;
- 63 188 115 ÷ 2 = 31 594 057 + 1;
- 31 594 057 ÷ 2 = 15 797 028 + 1;
- 15 797 028 ÷ 2 = 7 898 514 + 0;
- 7 898 514 ÷ 2 = 3 949 257 + 0;
- 3 949 257 ÷ 2 = 1 974 628 + 1;
- 1 974 628 ÷ 2 = 987 314 + 0;
- 987 314 ÷ 2 = 493 657 + 0;
- 493 657 ÷ 2 = 246 828 + 1;
- 246 828 ÷ 2 = 123 414 + 0;
- 123 414 ÷ 2 = 61 707 + 0;
- 61 707 ÷ 2 = 30 853 + 1;
- 30 853 ÷ 2 = 15 426 + 1;
- 15 426 ÷ 2 = 7 713 + 0;
- 7 713 ÷ 2 = 3 856 + 1;
- 3 856 ÷ 2 = 1 928 + 0;
- 1 928 ÷ 2 = 964 + 0;
- 964 ÷ 2 = 482 + 0;
- 482 ÷ 2 = 241 + 0;
- 241 ÷ 2 = 120 + 1;
- 120 ÷ 2 = 60 + 0;
- 60 ÷ 2 = 30 + 0;
- 30 ÷ 2 = 15 + 0;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 011 009 851(10) = 11 1100 0100 0010 1100 1001 0011 1011(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 30.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 30,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 1 011 009 851(10) converted to signed binary in one's complement representation: