1. Start with the positive version of the number:
|-585 622| = 585 622
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 585 622 ÷ 2 = 292 811 + 0;
- 292 811 ÷ 2 = 146 405 + 1;
- 146 405 ÷ 2 = 73 202 + 1;
- 73 202 ÷ 2 = 36 601 + 0;
- 36 601 ÷ 2 = 18 300 + 1;
- 18 300 ÷ 2 = 9 150 + 0;
- 9 150 ÷ 2 = 4 575 + 0;
- 4 575 ÷ 2 = 2 287 + 1;
- 2 287 ÷ 2 = 1 143 + 1;
- 1 143 ÷ 2 = 571 + 1;
- 571 ÷ 2 = 285 + 1;
- 285 ÷ 2 = 142 + 1;
- 142 ÷ 2 = 71 + 0;
- 71 ÷ 2 = 35 + 1;
- 35 ÷ 2 = 17 + 1;
- 17 ÷ 2 = 8 + 1;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
585 622(10) = 1000 1110 1111 1001 0110(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 20.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 20,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.