1. Start with the positive version of the number:
|-534 642 851| = 534 642 851
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 534 642 851 ÷ 2 = 267 321 425 + 1;
- 267 321 425 ÷ 2 = 133 660 712 + 1;
- 133 660 712 ÷ 2 = 66 830 356 + 0;
- 66 830 356 ÷ 2 = 33 415 178 + 0;
- 33 415 178 ÷ 2 = 16 707 589 + 0;
- 16 707 589 ÷ 2 = 8 353 794 + 1;
- 8 353 794 ÷ 2 = 4 176 897 + 0;
- 4 176 897 ÷ 2 = 2 088 448 + 1;
- 2 088 448 ÷ 2 = 1 044 224 + 0;
- 1 044 224 ÷ 2 = 522 112 + 0;
- 522 112 ÷ 2 = 261 056 + 0;
- 261 056 ÷ 2 = 130 528 + 0;
- 130 528 ÷ 2 = 65 264 + 0;
- 65 264 ÷ 2 = 32 632 + 0;
- 32 632 ÷ 2 = 16 316 + 0;
- 16 316 ÷ 2 = 8 158 + 0;
- 8 158 ÷ 2 = 4 079 + 0;
- 4 079 ÷ 2 = 2 039 + 1;
- 2 039 ÷ 2 = 1 019 + 1;
- 1 019 ÷ 2 = 509 + 1;
- 509 ÷ 2 = 254 + 1;
- 254 ÷ 2 = 127 + 0;
- 127 ÷ 2 = 63 + 1;
- 63 ÷ 2 = 31 + 1;
- 31 ÷ 2 = 15 + 1;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
534 642 851(10) = 1 1111 1101 1110 0000 0000 1010 0011(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 29.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 29,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.