1. Start with the positive version of the number:
|-3 131 313 141| = 3 131 313 141
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 3 131 313 141 ÷ 2 = 1 565 656 570 + 1;
- 1 565 656 570 ÷ 2 = 782 828 285 + 0;
- 782 828 285 ÷ 2 = 391 414 142 + 1;
- 391 414 142 ÷ 2 = 195 707 071 + 0;
- 195 707 071 ÷ 2 = 97 853 535 + 1;
- 97 853 535 ÷ 2 = 48 926 767 + 1;
- 48 926 767 ÷ 2 = 24 463 383 + 1;
- 24 463 383 ÷ 2 = 12 231 691 + 1;
- 12 231 691 ÷ 2 = 6 115 845 + 1;
- 6 115 845 ÷ 2 = 3 057 922 + 1;
- 3 057 922 ÷ 2 = 1 528 961 + 0;
- 1 528 961 ÷ 2 = 764 480 + 1;
- 764 480 ÷ 2 = 382 240 + 0;
- 382 240 ÷ 2 = 191 120 + 0;
- 191 120 ÷ 2 = 95 560 + 0;
- 95 560 ÷ 2 = 47 780 + 0;
- 47 780 ÷ 2 = 23 890 + 0;
- 23 890 ÷ 2 = 11 945 + 0;
- 11 945 ÷ 2 = 5 972 + 1;
- 5 972 ÷ 2 = 2 986 + 0;
- 2 986 ÷ 2 = 1 493 + 0;
- 1 493 ÷ 2 = 746 + 1;
- 746 ÷ 2 = 373 + 0;
- 373 ÷ 2 = 186 + 1;
- 186 ÷ 2 = 93 + 0;
- 93 ÷ 2 = 46 + 1;
- 46 ÷ 2 = 23 + 0;
- 23 ÷ 2 = 11 + 1;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
3 131 313 141(10) = 1011 1010 1010 0100 0000 1011 1111 0101(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 32.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 32,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
5. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.