1. Start with the positive version of the number:
|-2 958 918| = 2 958 918
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 2 958 918 ÷ 2 = 1 479 459 + 0;
- 1 479 459 ÷ 2 = 739 729 + 1;
- 739 729 ÷ 2 = 369 864 + 1;
- 369 864 ÷ 2 = 184 932 + 0;
- 184 932 ÷ 2 = 92 466 + 0;
- 92 466 ÷ 2 = 46 233 + 0;
- 46 233 ÷ 2 = 23 116 + 1;
- 23 116 ÷ 2 = 11 558 + 0;
- 11 558 ÷ 2 = 5 779 + 0;
- 5 779 ÷ 2 = 2 889 + 1;
- 2 889 ÷ 2 = 1 444 + 1;
- 1 444 ÷ 2 = 722 + 0;
- 722 ÷ 2 = 361 + 0;
- 361 ÷ 2 = 180 + 1;
- 180 ÷ 2 = 90 + 0;
- 90 ÷ 2 = 45 + 0;
- 45 ÷ 2 = 22 + 1;
- 22 ÷ 2 = 11 + 0;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
2 958 918(10) = 10 1101 0010 0110 0100 0110(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 22.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 22,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.