1. Start with the positive version of the number:
|-2 146 960 131| = 2 146 960 131
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 2 146 960 131 ÷ 2 = 1 073 480 065 + 1;
- 1 073 480 065 ÷ 2 = 536 740 032 + 1;
- 536 740 032 ÷ 2 = 268 370 016 + 0;
- 268 370 016 ÷ 2 = 134 185 008 + 0;
- 134 185 008 ÷ 2 = 67 092 504 + 0;
- 67 092 504 ÷ 2 = 33 546 252 + 0;
- 33 546 252 ÷ 2 = 16 773 126 + 0;
- 16 773 126 ÷ 2 = 8 386 563 + 0;
- 8 386 563 ÷ 2 = 4 193 281 + 1;
- 4 193 281 ÷ 2 = 2 096 640 + 1;
- 2 096 640 ÷ 2 = 1 048 320 + 0;
- 1 048 320 ÷ 2 = 524 160 + 0;
- 524 160 ÷ 2 = 262 080 + 0;
- 262 080 ÷ 2 = 131 040 + 0;
- 131 040 ÷ 2 = 65 520 + 0;
- 65 520 ÷ 2 = 32 760 + 0;
- 32 760 ÷ 2 = 16 380 + 0;
- 16 380 ÷ 2 = 8 190 + 0;
- 8 190 ÷ 2 = 4 095 + 0;
- 4 095 ÷ 2 = 2 047 + 1;
- 2 047 ÷ 2 = 1 023 + 1;
- 1 023 ÷ 2 = 511 + 1;
- 511 ÷ 2 = 255 + 1;
- 255 ÷ 2 = 127 + 1;
- 127 ÷ 2 = 63 + 1;
- 63 ÷ 2 = 31 + 1;
- 31 ÷ 2 = 15 + 1;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
2 146 960 131(10) = 111 1111 1111 1000 0000 0011 0000 0011(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.