1. Start with the positive version of the number:
|-1 962 934 292| = 1 962 934 292
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 962 934 292 ÷ 2 = 981 467 146 + 0;
- 981 467 146 ÷ 2 = 490 733 573 + 0;
- 490 733 573 ÷ 2 = 245 366 786 + 1;
- 245 366 786 ÷ 2 = 122 683 393 + 0;
- 122 683 393 ÷ 2 = 61 341 696 + 1;
- 61 341 696 ÷ 2 = 30 670 848 + 0;
- 30 670 848 ÷ 2 = 15 335 424 + 0;
- 15 335 424 ÷ 2 = 7 667 712 + 0;
- 7 667 712 ÷ 2 = 3 833 856 + 0;
- 3 833 856 ÷ 2 = 1 916 928 + 0;
- 1 916 928 ÷ 2 = 958 464 + 0;
- 958 464 ÷ 2 = 479 232 + 0;
- 479 232 ÷ 2 = 239 616 + 0;
- 239 616 ÷ 2 = 119 808 + 0;
- 119 808 ÷ 2 = 59 904 + 0;
- 59 904 ÷ 2 = 29 952 + 0;
- 29 952 ÷ 2 = 14 976 + 0;
- 14 976 ÷ 2 = 7 488 + 0;
- 7 488 ÷ 2 = 3 744 + 0;
- 3 744 ÷ 2 = 1 872 + 0;
- 1 872 ÷ 2 = 936 + 0;
- 936 ÷ 2 = 468 + 0;
- 468 ÷ 2 = 234 + 0;
- 234 ÷ 2 = 117 + 0;
- 117 ÷ 2 = 58 + 1;
- 58 ÷ 2 = 29 + 0;
- 29 ÷ 2 = 14 + 1;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 962 934 292(10) = 111 0101 0000 0000 0000 0000 0001 0100(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.