1. Start with the positive version of the number:
|-1 962 934 235| = 1 962 934 235
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 962 934 235 ÷ 2 = 981 467 117 + 1;
- 981 467 117 ÷ 2 = 490 733 558 + 1;
- 490 733 558 ÷ 2 = 245 366 779 + 0;
- 245 366 779 ÷ 2 = 122 683 389 + 1;
- 122 683 389 ÷ 2 = 61 341 694 + 1;
- 61 341 694 ÷ 2 = 30 670 847 + 0;
- 30 670 847 ÷ 2 = 15 335 423 + 1;
- 15 335 423 ÷ 2 = 7 667 711 + 1;
- 7 667 711 ÷ 2 = 3 833 855 + 1;
- 3 833 855 ÷ 2 = 1 916 927 + 1;
- 1 916 927 ÷ 2 = 958 463 + 1;
- 958 463 ÷ 2 = 479 231 + 1;
- 479 231 ÷ 2 = 239 615 + 1;
- 239 615 ÷ 2 = 119 807 + 1;
- 119 807 ÷ 2 = 59 903 + 1;
- 59 903 ÷ 2 = 29 951 + 1;
- 29 951 ÷ 2 = 14 975 + 1;
- 14 975 ÷ 2 = 7 487 + 1;
- 7 487 ÷ 2 = 3 743 + 1;
- 3 743 ÷ 2 = 1 871 + 1;
- 1 871 ÷ 2 = 935 + 1;
- 935 ÷ 2 = 467 + 1;
- 467 ÷ 2 = 233 + 1;
- 233 ÷ 2 = 116 + 1;
- 116 ÷ 2 = 58 + 0;
- 58 ÷ 2 = 29 + 0;
- 29 ÷ 2 = 14 + 1;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 962 934 235(10) = 111 0100 1111 1111 1111 1111 1101 1011(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.