1. Start with the positive version of the number:
|-1 869 596 910| = 1 869 596 910
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 869 596 910 ÷ 2 = 934 798 455 + 0;
- 934 798 455 ÷ 2 = 467 399 227 + 1;
- 467 399 227 ÷ 2 = 233 699 613 + 1;
- 233 699 613 ÷ 2 = 116 849 806 + 1;
- 116 849 806 ÷ 2 = 58 424 903 + 0;
- 58 424 903 ÷ 2 = 29 212 451 + 1;
- 29 212 451 ÷ 2 = 14 606 225 + 1;
- 14 606 225 ÷ 2 = 7 303 112 + 1;
- 7 303 112 ÷ 2 = 3 651 556 + 0;
- 3 651 556 ÷ 2 = 1 825 778 + 0;
- 1 825 778 ÷ 2 = 912 889 + 0;
- 912 889 ÷ 2 = 456 444 + 1;
- 456 444 ÷ 2 = 228 222 + 0;
- 228 222 ÷ 2 = 114 111 + 0;
- 114 111 ÷ 2 = 57 055 + 1;
- 57 055 ÷ 2 = 28 527 + 1;
- 28 527 ÷ 2 = 14 263 + 1;
- 14 263 ÷ 2 = 7 131 + 1;
- 7 131 ÷ 2 = 3 565 + 1;
- 3 565 ÷ 2 = 1 782 + 1;
- 1 782 ÷ 2 = 891 + 0;
- 891 ÷ 2 = 445 + 1;
- 445 ÷ 2 = 222 + 1;
- 222 ÷ 2 = 111 + 0;
- 111 ÷ 2 = 55 + 1;
- 55 ÷ 2 = 27 + 1;
- 27 ÷ 2 = 13 + 1;
- 13 ÷ 2 = 6 + 1;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 869 596 910(10) = 110 1111 0110 1111 1100 1000 1110 1110(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.