1. Start with the positive version of the number:
|-1 140 700 510| = 1 140 700 510
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 140 700 510 ÷ 2 = 570 350 255 + 0;
- 570 350 255 ÷ 2 = 285 175 127 + 1;
- 285 175 127 ÷ 2 = 142 587 563 + 1;
- 142 587 563 ÷ 2 = 71 293 781 + 1;
- 71 293 781 ÷ 2 = 35 646 890 + 1;
- 35 646 890 ÷ 2 = 17 823 445 + 0;
- 17 823 445 ÷ 2 = 8 911 722 + 1;
- 8 911 722 ÷ 2 = 4 455 861 + 0;
- 4 455 861 ÷ 2 = 2 227 930 + 1;
- 2 227 930 ÷ 2 = 1 113 965 + 0;
- 1 113 965 ÷ 2 = 556 982 + 1;
- 556 982 ÷ 2 = 278 491 + 0;
- 278 491 ÷ 2 = 139 245 + 1;
- 139 245 ÷ 2 = 69 622 + 1;
- 69 622 ÷ 2 = 34 811 + 0;
- 34 811 ÷ 2 = 17 405 + 1;
- 17 405 ÷ 2 = 8 702 + 1;
- 8 702 ÷ 2 = 4 351 + 0;
- 4 351 ÷ 2 = 2 175 + 1;
- 2 175 ÷ 2 = 1 087 + 1;
- 1 087 ÷ 2 = 543 + 1;
- 543 ÷ 2 = 271 + 1;
- 271 ÷ 2 = 135 + 1;
- 135 ÷ 2 = 67 + 1;
- 67 ÷ 2 = 33 + 1;
- 33 ÷ 2 = 16 + 1;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 140 700 510(10) = 100 0011 1111 1101 1011 0101 0101 1110(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.