1. Start with the positive version of the number:
|-1 139 850 809| = 1 139 850 809
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 139 850 809 ÷ 2 = 569 925 404 + 1;
- 569 925 404 ÷ 2 = 284 962 702 + 0;
- 284 962 702 ÷ 2 = 142 481 351 + 0;
- 142 481 351 ÷ 2 = 71 240 675 + 1;
- 71 240 675 ÷ 2 = 35 620 337 + 1;
- 35 620 337 ÷ 2 = 17 810 168 + 1;
- 17 810 168 ÷ 2 = 8 905 084 + 0;
- 8 905 084 ÷ 2 = 4 452 542 + 0;
- 4 452 542 ÷ 2 = 2 226 271 + 0;
- 2 226 271 ÷ 2 = 1 113 135 + 1;
- 1 113 135 ÷ 2 = 556 567 + 1;
- 556 567 ÷ 2 = 278 283 + 1;
- 278 283 ÷ 2 = 139 141 + 1;
- 139 141 ÷ 2 = 69 570 + 1;
- 69 570 ÷ 2 = 34 785 + 0;
- 34 785 ÷ 2 = 17 392 + 1;
- 17 392 ÷ 2 = 8 696 + 0;
- 8 696 ÷ 2 = 4 348 + 0;
- 4 348 ÷ 2 = 2 174 + 0;
- 2 174 ÷ 2 = 1 087 + 0;
- 1 087 ÷ 2 = 543 + 1;
- 543 ÷ 2 = 271 + 1;
- 271 ÷ 2 = 135 + 1;
- 135 ÷ 2 = 67 + 1;
- 67 ÷ 2 = 33 + 1;
- 33 ÷ 2 = 16 + 1;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 139 850 809(10) = 100 0011 1111 0000 1011 1110 0011 1001(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.