1. Start with the positive version of the number:
|-1 109 964| = 1 109 964
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 109 964 ÷ 2 = 554 982 + 0;
- 554 982 ÷ 2 = 277 491 + 0;
- 277 491 ÷ 2 = 138 745 + 1;
- 138 745 ÷ 2 = 69 372 + 1;
- 69 372 ÷ 2 = 34 686 + 0;
- 34 686 ÷ 2 = 17 343 + 0;
- 17 343 ÷ 2 = 8 671 + 1;
- 8 671 ÷ 2 = 4 335 + 1;
- 4 335 ÷ 2 = 2 167 + 1;
- 2 167 ÷ 2 = 1 083 + 1;
- 1 083 ÷ 2 = 541 + 1;
- 541 ÷ 2 = 270 + 1;
- 270 ÷ 2 = 135 + 0;
- 135 ÷ 2 = 67 + 1;
- 67 ÷ 2 = 33 + 1;
- 33 ÷ 2 = 16 + 1;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 109 964(10) = 1 0000 1110 1111 1100 1100(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 21.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 21,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.