1. Start with the positive version of the number:
|-1 011 335| = 1 011 335
2. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 011 335 ÷ 2 = 505 667 + 1;
- 505 667 ÷ 2 = 252 833 + 1;
- 252 833 ÷ 2 = 126 416 + 1;
- 126 416 ÷ 2 = 63 208 + 0;
- 63 208 ÷ 2 = 31 604 + 0;
- 31 604 ÷ 2 = 15 802 + 0;
- 15 802 ÷ 2 = 7 901 + 0;
- 7 901 ÷ 2 = 3 950 + 1;
- 3 950 ÷ 2 = 1 975 + 0;
- 1 975 ÷ 2 = 987 + 1;
- 987 ÷ 2 = 493 + 1;
- 493 ÷ 2 = 246 + 1;
- 246 ÷ 2 = 123 + 0;
- 123 ÷ 2 = 61 + 1;
- 61 ÷ 2 = 30 + 1;
- 30 ÷ 2 = 15 + 0;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 011 335(10) = 1111 0110 1110 1000 0111(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 20.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 20,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.