What are the required steps to convert base 10 decimal system
number 989 981 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 989 981 ÷ 2 = 494 990 + 1;
- 494 990 ÷ 2 = 247 495 + 0;
- 247 495 ÷ 2 = 123 747 + 1;
- 123 747 ÷ 2 = 61 873 + 1;
- 61 873 ÷ 2 = 30 936 + 1;
- 30 936 ÷ 2 = 15 468 + 0;
- 15 468 ÷ 2 = 7 734 + 0;
- 7 734 ÷ 2 = 3 867 + 0;
- 3 867 ÷ 2 = 1 933 + 1;
- 1 933 ÷ 2 = 966 + 1;
- 966 ÷ 2 = 483 + 0;
- 483 ÷ 2 = 241 + 1;
- 241 ÷ 2 = 120 + 1;
- 120 ÷ 2 = 60 + 0;
- 60 ÷ 2 = 30 + 0;
- 30 ÷ 2 = 15 + 0;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
989 981(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
989 981 (base 10) = 1111 0001 1011 0001 1101 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.