What are the required steps to convert base 10 decimal system
number 720 483 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 720 483 ÷ 2 = 360 241 + 1;
- 360 241 ÷ 2 = 180 120 + 1;
- 180 120 ÷ 2 = 90 060 + 0;
- 90 060 ÷ 2 = 45 030 + 0;
- 45 030 ÷ 2 = 22 515 + 0;
- 22 515 ÷ 2 = 11 257 + 1;
- 11 257 ÷ 2 = 5 628 + 1;
- 5 628 ÷ 2 = 2 814 + 0;
- 2 814 ÷ 2 = 1 407 + 0;
- 1 407 ÷ 2 = 703 + 1;
- 703 ÷ 2 = 351 + 1;
- 351 ÷ 2 = 175 + 1;
- 175 ÷ 2 = 87 + 1;
- 87 ÷ 2 = 43 + 1;
- 43 ÷ 2 = 21 + 1;
- 21 ÷ 2 = 10 + 1;
- 10 ÷ 2 = 5 + 0;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
720 483(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
720 483 (base 10) = 1010 1111 1110 0110 0011 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.