What are the required steps to convert base 10 decimal system
number 6 547 946 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 6 547 946 ÷ 2 = 3 273 973 + 0;
- 3 273 973 ÷ 2 = 1 636 986 + 1;
- 1 636 986 ÷ 2 = 818 493 + 0;
- 818 493 ÷ 2 = 409 246 + 1;
- 409 246 ÷ 2 = 204 623 + 0;
- 204 623 ÷ 2 = 102 311 + 1;
- 102 311 ÷ 2 = 51 155 + 1;
- 51 155 ÷ 2 = 25 577 + 1;
- 25 577 ÷ 2 = 12 788 + 1;
- 12 788 ÷ 2 = 6 394 + 0;
- 6 394 ÷ 2 = 3 197 + 0;
- 3 197 ÷ 2 = 1 598 + 1;
- 1 598 ÷ 2 = 799 + 0;
- 799 ÷ 2 = 399 + 1;
- 399 ÷ 2 = 199 + 1;
- 199 ÷ 2 = 99 + 1;
- 99 ÷ 2 = 49 + 1;
- 49 ÷ 2 = 24 + 1;
- 24 ÷ 2 = 12 + 0;
- 12 ÷ 2 = 6 + 0;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
6 547 946(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
6 547 946 (base 10) = 110 0011 1110 1001 1110 1010 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.