What are the required steps to convert base 10 decimal system
number 3 325 909 398 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 3 325 909 398 ÷ 2 = 1 662 954 699 + 0;
- 1 662 954 699 ÷ 2 = 831 477 349 + 1;
- 831 477 349 ÷ 2 = 415 738 674 + 1;
- 415 738 674 ÷ 2 = 207 869 337 + 0;
- 207 869 337 ÷ 2 = 103 934 668 + 1;
- 103 934 668 ÷ 2 = 51 967 334 + 0;
- 51 967 334 ÷ 2 = 25 983 667 + 0;
- 25 983 667 ÷ 2 = 12 991 833 + 1;
- 12 991 833 ÷ 2 = 6 495 916 + 1;
- 6 495 916 ÷ 2 = 3 247 958 + 0;
- 3 247 958 ÷ 2 = 1 623 979 + 0;
- 1 623 979 ÷ 2 = 811 989 + 1;
- 811 989 ÷ 2 = 405 994 + 1;
- 405 994 ÷ 2 = 202 997 + 0;
- 202 997 ÷ 2 = 101 498 + 1;
- 101 498 ÷ 2 = 50 749 + 0;
- 50 749 ÷ 2 = 25 374 + 1;
- 25 374 ÷ 2 = 12 687 + 0;
- 12 687 ÷ 2 = 6 343 + 1;
- 6 343 ÷ 2 = 3 171 + 1;
- 3 171 ÷ 2 = 1 585 + 1;
- 1 585 ÷ 2 = 792 + 1;
- 792 ÷ 2 = 396 + 0;
- 396 ÷ 2 = 198 + 0;
- 198 ÷ 2 = 99 + 0;
- 99 ÷ 2 = 49 + 1;
- 49 ÷ 2 = 24 + 1;
- 24 ÷ 2 = 12 + 0;
- 12 ÷ 2 = 6 + 0;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
3 325 909 398(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
3 325 909 398 (base 10) = 1100 0110 0011 1101 0101 1001 1001 0110 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.