What are the required steps to convert base 10 decimal system
number 15 329 530 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 15 329 530 ÷ 2 = 7 664 765 + 0;
- 7 664 765 ÷ 2 = 3 832 382 + 1;
- 3 832 382 ÷ 2 = 1 916 191 + 0;
- 1 916 191 ÷ 2 = 958 095 + 1;
- 958 095 ÷ 2 = 479 047 + 1;
- 479 047 ÷ 2 = 239 523 + 1;
- 239 523 ÷ 2 = 119 761 + 1;
- 119 761 ÷ 2 = 59 880 + 1;
- 59 880 ÷ 2 = 29 940 + 0;
- 29 940 ÷ 2 = 14 970 + 0;
- 14 970 ÷ 2 = 7 485 + 0;
- 7 485 ÷ 2 = 3 742 + 1;
- 3 742 ÷ 2 = 1 871 + 0;
- 1 871 ÷ 2 = 935 + 1;
- 935 ÷ 2 = 467 + 1;
- 467 ÷ 2 = 233 + 1;
- 233 ÷ 2 = 116 + 1;
- 116 ÷ 2 = 58 + 0;
- 58 ÷ 2 = 29 + 0;
- 29 ÷ 2 = 14 + 1;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
15 329 530(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
15 329 530 (base 10) = 1110 1001 1110 1000 1111 1010 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.